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1. Integers 2. Fractions and Decimals 3. Data Handling
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7. Comparing Quantities 8. Rational Numbers 9. Perimeter and Area
10. Algebraic Expressions 11. Exponents and Powers 12. Symmetry
13. Visualising Solid Shapes

Content On This Page
Example 1 to 3 (Before Exercise 10.1) Exercise 10.1 Example 4 to 6 (Before Exercise 10.2)
Exercise 10.2


Chapter 10 Algebraic Expressions

Welcome to the solutions guide for Chapter 10, "Algebraic Expressions," a fundamental pillar of algebra within the latest Class 7 NCERT mathematics textbook framework for the academic session 2024-25. Algebraic expressions form the very language of algebra, allowing us to represent relationships and solve problems in a concise and general way. Moving beyond simple equations, this chapter focuses on understanding the structure of these expressions and mastering the essential operations of addition and subtraction. This resource provides comprehensive, step-by-step support for all exercises, aiming to build a strong foundation for future algebraic studies.

The journey begins by dissecting the anatomy of algebraic expressions. The solutions provided here meticulously guide students in identifying the core components:

Understanding this terminology is crucial for communicating effectively about algebra. The solutions also clarify the classification of expressions based on the number of terms they contain: monomial (one term), binomial (two terms), trinomial (three terms), and polynomial (one or more terms). A critical distinction explained is between like terms (terms having the same literal factors raised to the same powers, e.g., $7ab$ and $-2ab$) and unlike terms (terms with different literal factors or different powers, e.g., $5x^2$ and $3x$).

A primary focus of this chapter, and therefore these solutions, is mastering the addition and subtraction of algebraic expressions. This involves the fundamental principle of combining only like terms. The solutions demonstrate two prevalent methods for performing these operations:

  1. The Horizontal Method: This involves writing the expressions in a line, removing brackets (paying careful attention to sign changes when subtracting), and then grouping all like terms together before combining their coefficients.
  2. The Vertical Method: This technique involves arranging the expressions one below the other such that like terms align in the same column, making it easier to add or subtract their coefficients vertically, similar to arithmetic addition/subtraction.
Both methods are illustrated with clear, step-by-step procedures, emphasizing accuracy in sign handling and combination of terms.

Furthermore, the solutions guide students through the process of evaluating algebraic expressions. This involves substituting given numerical values for the variables within an expression and then simplifying the resulting numerical expression using the standard order of operations (BODMAS/PEMDAS). For example, finding the value of $3a^2 - 2b$ when $a=2$ and $b=-1$ requires careful substitution: $3(2)^2 - 2(-1) = 3(4) - (-2) = 12 + 2 = 14$. The solutions highlight using parentheses during substitution to avoid errors, especially with negative numbers. Additionally, some exercises involve translating simple verbal descriptions or situations into algebraic expressions, a foundational skill for problem-solving, and the solutions demonstrate this translation process.

Regarding the rationalized syllabus for 2024-25, Chapter 10, "Algebraic Expressions," in the Class 7 NCERT textbook maintains its core focus on identifying components, classifying expressions, adding, subtracting, and evaluating algebraic expressions. The rationalization primarily involved adjusting the complexity and quantity of exercises, ensuring a solid understanding of these fundamental algebraic manipulations without delving into overly complicated expressions or operations at this stage. By utilizing these detailed solutions, students can gain clarity on the structure and vocabulary of algebra, master addition and subtraction techniques, become proficient in evaluating expressions, and build the essential skills needed for subsequent algebraic topics.



Example 1 to 3 (Before Exercise 10.1)

Example 1. Identify, in the following expressions, terms which are not constants. Give their numerical coefficients:

xy + 4 , 13 – y2 , 13 – y + 5y2 , 4p2q – 3pq2 + 5

Answer:

Solution:


In an algebraic expression, terms are parts separated by addition or subtraction. A constant term is a term that does not contain any variables. Terms which are not constants contain variables. The numerical coefficient of a term is the number that multiplies the variable part of the term.


Let's examine each expression:


Expression: xy + 4

Terms are xy and 4.

The term '4' is a constant term.

The term 'xy' is not a constant term as it contains variables x and y.

The numerical coefficient of the term xy is 1 (since $xy = 1 \times xy$).


Expression: 13 – y2

Terms are 13 and $-y^2$.

The term '13' is a constant term.

The term '$-y^2$' is not a constant term as it contains the variable y.

The numerical coefficient of the term $-y^2$ is -1 (since $-y^2 = -1 \times y^2$).


Expression: 13 – y + 5y2

Terms are 13, -y, and $5y^2$.

The term '13' is a constant term.

The terms '-y' and '$5y^2$' are not constant terms as they contain the variable y.

The numerical coefficient of the term -y is -1 (since $-y = -1 \times y$).

The numerical coefficient of the term $5y^2$ is 5.


Expression: 4p2q – 3pq2 + 5

Terms are $4p^2q$, $-3pq^2$, and 5.

The term '5' is a constant term.

The terms '$4p^2q$' and '$-3pq^2$' are not constant terms as they contain variables p and q.

The numerical coefficient of the term $4p^2q$ is 4.

The numerical coefficient of the term $-3pq^2$ is -3.


Summarizing the terms which are not constants and their numerical coefficients:

Expression Term (not constant) Numerical Coefficient
xy + 4xy1
13 – y2-y2-1
13 – y + 5y2-y-1
13 – y + 5y25y25
4p2q – 3pq2 + 54p2q4
4p2q – 3pq2 + 5-3pq2-3

Example 2.

(a) What are the coefficients of x in the following expressions?

4x – 3y , 8 – x + y , y2x – y , 2z – 5xz

(b) What are the coefficients of y in the following expressions?

4x – 3y , 8 + yz , yz2 + 5 , my + m

Answer:

Solution:


The coefficient of a variable in a term is the factor that multiplies that variable (including the sign and any other variables/numbers in the term, but excluding the variable itself for which we are finding the coefficient).


(a) Coefficients of x:


Expression: 4x – 3y

Terms containing x: 4x.

In the term 4x, the factor multiplying x is 4.

The coefficient of x is 4.


Expression: 8 – x + y

Terms containing x: -x.

In the term -x, which can be written as $-1 \times x$, the factor multiplying x is -1.

The coefficient of x is -1.


Expression: y2x – y

Terms containing x: $y^2x$.

In the term $y^2x$, the factor multiplying x is $y^2$.

The coefficient of x is $y^2$.


Expression: 2z – 5xz

Terms containing x: -5xz.

In the term -5xz, the factors multiplying x are -5 and z. So, the factor multiplying x is -5z.

The coefficient of x is -5z.


Summary of coefficients of x:

Expression Term(s) containing x Coefficient of x
4x – 3y4x4
8 – x + y-x-1
y2x – yy2xy2
2z – 5xz-5xz-5z

(b) What are the coefficients of y in the following expressions?


Expression: 4x – 3y

Terms containing y: -3y.

In the term -3y, the factor multiplying y is -3.

The coefficient of y is -3.


Expression: 8 + yz

Terms containing y: yz.

In the term yz, the factor multiplying y is z.

The coefficient of y is z.


Expression: yz2 + 5

Terms containing y: $yz^2$.

In the term $yz^2$, the factor multiplying y is $z^2$.

The coefficient of y is $z^2$.


Expression: my + m

Terms containing y: my.

In the term my, the factor multiplying y is m.

The coefficient of y is m.


Summary of coefficients of y:

Expression Term(s) containing y Coefficient of y
4x – 3y-3y-3
8 + yzyzz
yz2 + 5yz2z2
my + mmym

Example 3. State with reasons, which of the following pairs of terms are of like terms and which are of unlike terms:

(i) 7x , 12y

(ii) 15x , –21x

(iii) – 4ab , 7ba

(iv) 3xy , 3x

(v) 6xy2 , 9x2y

(vi) pq2 , – 4pq2

(vii) mn2 , 10mn

Answer:

Solution:


Like terms are terms that have the same variables raised to the same powers. The numerical coefficients do not matter. Unlike terms are terms that do not have the same variables or the same powers of the variables.


Let's examine each pair of terms:


(i) 7x , 12y

The variables are x and y. The variables are different.

These are unlike terms.

Reason: The terms have different variables.


(ii) 15x , –21x

The variable in both terms is x. The power of x in both terms is 1.

These are like terms.

Reason: The terms have the same variable raised to the same power (x1).


(iii) – 4ab , 7ba

The variables in the first term are a and b, both with power 1. The variables in the second term are b and a, both with power 1. Since multiplication is commutative ($ab = ba$), the variable parts are the same.

These are like terms.

Reason: The terms have the same variables (a and b) raised to the same powers (a1 and b1), although written in a different order.


(iv) 3xy , 3x

The variables in the first term are x and y, both with power 1. The variable in the second term is x with power 1.

These are unlike terms.

Reason: The terms do not have the same variables (the first term has y, but the second term does not).


(v) 6xy2 , 9x2y

In the first term, the power of x is 1 and the power of y is 2. ($xy^2 = x^1y^2$)

In the second term, the power of x is 2 and the power of y is 1. ($x^2y = x^2y^1$)

The powers of the variables are not the same for both terms.

These are unlike terms.

Reason: The terms have the same variables (x and y), but the powers of the variables are different.


(vi) pq2 , – 4pq2

In the first term, the variable part is $pq^2$ (which is $p^1q^2$).

In the second term, the variable part is $pq^2$ (which is $p^1q^2$).

The variables and their powers are the same in both terms.

These are like terms.

Reason: The terms have the same variables (p and q) raised to the same powers (p1 and q2).


(vii) mn2 , 10mn

In the first term, the variable part is $mn^2$ (which is $m^1n^2$).

In the second term, the variable part is $mn$ (which is $m^1n^1$).

The powers of the variable n are different ($n^2$ vs $n^1$).

These are unlike terms.

Reason: The terms have the same variables (m and n), but the powers of the variable n are different.


Summary:

Pair of terms Like/Unlike Terms Reason
7x , 12yUnlike termsDifferent variables.
15x , –21xLike termsSame variable (x) with same power (1).
– 4ab , 7baLike termsSame variables (a, b) with same powers (a1, b1).
3xy , 3xUnlike termsDifferent variables (first term has y, second does not).
6xy2 , 9x2yUnlike termsSame variables, but different powers (x1y2 vs x2y1).
pq2 , – 4pq2Like termsSame variables (p, q) with same powers (p1, q2).
mn2 , 10mnUnlike termsSame variables, but different powers (m1n2 vs m1n1).


Exercise 10.1

Question 1. Get the algebraic expressions in the following cases using variables, constants and arithmetic operations.

(i) Subtraction of z from y.

(ii) One-half of the sum of numbers x and y.

(iii) The number z multiplied by itself.

(iv) One-fourth of the product of numbers p and q.

(v) Numbers x and y both squared and added.

(vi) Number 5 added to three times the product of numbers m and n.

(vii) Product of numbers y and z subtracted from 10.

(viii) Sum of numbers a and b subtracted from their product.

Answer:

Solution:


We need to translate the given verbal statements into algebraic expressions using variables, constants, and arithmetic operations (+, -, $\times$, $\div$).


(i) Subtraction of z from y.

This means y minus z.

The expression is $y - z$.


(ii) One-half of the sum of numbers x and y.

First, find the sum of x and y: $x + y$.

Then, take one-half of the sum: $\frac{1}{2} \times (x+y)$ or $\frac{x+y}{2}$.

The expression is $\frac{1}{2}(x+y)$ or $\frac{x+y}{2}$.


(iii) The number z multiplied by itself.

This means z times z.

The expression is $z \times z$, which is written as $z^2$.


(iv) One-fourth of the product of numbers p and q.

First, find the product of p and q: $p \times q$ or $pq$.

Then, take one-fourth of the product: $\frac{1}{4} \times pq$ or $\frac{pq}{4}$.

The expression is $\frac{1}{4}pq$ or $\frac{pq}{4}$.


(v) Numbers x and y both squared and added.

First, square x: $x^2$.

Then, square y: $y^2$.

Finally, add the squared numbers: $x^2 + y^2$.

The expression is $x^2 + y^2$.


(vi) Number 5 added to three times the product of numbers m and n.

First, find the product of m and n: $mn$.

Then, find three times the product: $3 \times mn$ or $3mn$.

Finally, add 5 to this result: $3mn + 5$.

The expression is $3mn + 5$.


(vii) Product of numbers y and z subtracted from 10.

First, find the product of y and z: $yz$.

This product is subtracted from 10, meaning 10 minus the product.

The expression is $10 - yz$.


(viii) Sum of numbers a and b subtracted from their product.

First, find the sum of a and b: $a + b$.

Then, find the product of a and b: $ab$.

The sum is subtracted from the product, meaning the product minus the sum.

The expression is $ab - (a+b)$.


Summary of the algebraic expressions:

(i) $y - z$

(ii) $\frac{1}{2}(x+y)$ or $\frac{x+y}{2}$

(iii) $z^2$

(iv) $\frac{1}{4}pq$ or $\frac{pq}{4}$

(v) $x^2 + y^2$

(vi) $3mn + 5$

(vii) $10 - yz$

(viii) $ab - (a+b)$

Question 2.

(i) Identify the terms and their factors in the following expressions. Show the terms and factors by tree diagrams.

(a) x – 3

(b) 1 + x + x2

(c) y – y3

(d) 5xy2 + 7x2y

(e) – ab + 2b2 – 3a2

(ii) Identify terms and factors in the expressions given below:

(a) – 4x + 5

(b) – 4x + 5y

(c) 5y + 3y2

(d) xy + 2x2y2

(e) pq + q

(f) 1.2 ab – 2.4 b + 3.6 a

(g) $\frac{3}{4}x + \frac{1}{4}$

(h) 0.1 p2 + 0.2 q2

Answer:

Solution:


(i) Identification of terms and factors using tree diagrams:

(a) $x - 3$

Expression: $x - 3$

Terms: $x$, $-3$

Factors of $x$: $x$

Factors of $-3$: $-3$

Tree diagram for x - 3

(b) $1 + x + x^2$

Expression: $1 + x + x^2$

Terms: $1$, $x$, $x^2$

Factors of $1$: $1$

Factors of $x$: $x$

Factors of $x^2$: $x, x$

Tree diagram for 1 + x + x^2

(c) $y - y^3$

Expression: $y - y^3$

Terms: $y$, $-y^3$

Factors of $y$: $y$

Factors of $-y^3$: $-1, y, y, y$

Tree diagram for y - y^3

(d) $5xy^2 + 7x^2y$

Expression: $5xy^2 + 7x^2y$

Terms: $5xy^2$, $7x^2y$

Factors of $5xy^2$: $5, x, y, y$

Factors of $7x^2y$: $7, x, x, y$

Tree diagram for 5xy^2 + 7x^2y

(e) $- ab + 2b^2 - 3a^2$

Expression: $- ab + 2b^2 - 3a^2$

Terms: $-ab$, $2b^2$, $-3a^2$

Factors of $-ab$: $-1, a, b$

Factors of $2b^2$: $2, b, b$

Factors of $-3a^2$: $-3, a, a$

Tree diagram for -ab + 2b^2 - 3a^2

(ii) Identification of terms and factors:

(a) $-4x + 5$

Terms: $-4x$, $5$

Factors of $-4x$: $-4, x$

Factors of $5$: $5$


(b) $-4x + 5y$

Terms: $-4x$, $5y$

Factors of $-4x$: $-4, x$

Factors of $5y$: $5, y$


(c) $5y + 3y^2$

Terms: $5y$, $3y^2$

Factors of $5y$: $5, y$

Factors of $3y^2$: $3, y, y$


(d) $xy + 2x^2y^2$

Terms: $xy$, $2x^2y^2$

Factors of $xy$: $x, y$

Factors of $2x^2y^2$: $2, x, x, y, y$


(e) $pq + q$

Terms: $pq$, $q$

Factors of $pq$: $p, q$

Factors of $q$: $q$


(f) $1.2 ab – 2.4 b + 3.6 a$

Terms: $1.2ab$, $-2.4b$, $3.6a$

Factors of $1.2ab$: $1.2, a, b$

Factors of $-2.4b$: $-2.4, b$

Factors of $3.6a$: $3.6, a$


(g) $\frac{3}{4}x + \frac{1}{4}$

Terms: $\frac{3}{4}x$, $\frac{1}{4}$

Factors of $\frac{3}{4}x$: $\frac{3}{4}, x$

Factors of $\frac{1}{4}$: $\frac{1}{4}$


(h) $0.1 p^2 + 0.2 q^2$

Terms: $0.1p^2$, $0.2q^2$

Factors of $0.1p^2$: $0.1, p, p$

Factors of $0.2q^2$: $0.2, q, q$

Question 3. Identify the numerical coefficients of terms (other than constants) in the following expressions:

(i) 5 – 3t2

(ii) 1 + t + t2 + t3

(iii) x + 2xy + 3y

(iv) 100m + 1000n

(v) –p2q2 + 7pq

(vi) 1.2 a + 0.8 b

(vii) 3.14 r2

(viii) 2 (l + b)

(ix) 0.1 y + 0.01 y2

Answer:

(i) $5 - 3t^2$

Terms (other than constant): $-3t^2$

Numerical coefficient of $-3t^2$ is $-3$.


(ii) $1 + t + t^2 + t^3$

Terms (other than constant): $t$, $t^2$, $t^3$

Numerical coefficient of $t$ is $1$.

Numerical coefficient of $t^2$ is $1$.

Numerical coefficient of $t^3$ is $1$.


(iii) $x + 2xy + 3y$

Terms (other than constant): $x$, $2xy$, $3y$

Numerical coefficient of $x$ is $1$.

Numerical coefficient of $2xy$ is $2$.

Numerical coefficient of $3y$ is $3$.


(iv) $100m + 1000n$

Terms (other than constant): $100m$, $1000n$

Numerical coefficient of $100m$ is $100$.

Numerical coefficient of $1000n$ is $1000$.


(v) $-p^2q^2 + 7pq$

Terms (other than constant): $-p^2q^2$, $7pq$

Numerical coefficient of $-p^2q^2$ is $-1$.

Numerical coefficient of $7pq$ is $7$.


(vi) $1.2 a + 0.8 b$

Terms (other than constant): $1.2 a$, $0.8 b$

Numerical coefficient of $1.2 a$ is $1.2$.

Numerical coefficient of $0.8 b$ is $0.8$.


(vii) $3.14 r^2$

Terms (other than constant): $3.14 r^2$

Numerical coefficient of $3.14 r^2$ is $3.14$.


(viii) $2 (l + b) = 2l + 2b$

Terms (other than constant): $2l$, $2b$

Numerical coefficient of $2l$ is $2$.

Numerical coefficient of $2b$ is $2$.


(ix) $0.1 y + 0.01 y^2$

Terms (other than constant): $0.1 y$, $0.01 y^2$

Numerical coefficient of $0.1 y$ is $0.1$.

Numerical coefficient of $0.01 y^2$ is $0.01$.

Question 4.

(a) Identify terms which contain x and give the coefficient of x.

(i) y2x + y

(ii) 13y2 – 8yx

(iii) x + y + 2

(iv) 5 + z + zx

(v) 1 + x + xy

(vi) 12xy2 + 25

(vii) 7x + xy2

(b) Identify terms which contain y2 and give the coefficient of y2.

(i) 8 – xy2

(ii) 5y2 + 7x

(iii) 2x2y – 15xy2 + 7y2

Answer:

(a) Identify terms which contain $x$ and give the coefficient of $x$.

(i) $y^2x + y$

Term containing $x$: $y^2x$

Coefficient of $x$: $y^2$


(ii) $13y^2 – 8yx$

Term containing $x$: $-8yx$

Coefficient of $x$: $-8y$


(iii) $x + y + 2$

Term containing $x$: $x$

Coefficient of $x$: $1$


(iv) $5 + z + zx$

Term containing $x$: $zx$

Coefficient of $x$: $z$


(v) $1 + x + xy$

Terms containing $x$: $x$, $xy$

Coefficient of $x$ in $x$: $1$

Coefficient of $x$ in $xy$: $y$


(vi) $12xy^2 + 25$

Term containing $x$: $12xy^2$

Coefficient of $x$: $12y^2$


(vii) $7x + xy^2$

Terms containing $x$: $7x$, $xy^2$

Coefficient of $x$ in $7x$: $7$

Coefficient of $x$ in $xy^2$: $y^2$


(b) Identify terms which contain $y^2$ and give the coefficient of $y^2$.

(i) $8 – xy^2$

Term containing $y^2$: $-xy^2$

Coefficient of $y^2$: $-x$


(ii) $5y^2 + 7x$

Term containing $y^2$: $5y^2$

Coefficient of $y^2$: $5$


(iii) $2x^2y – 15xy^2 + 7y^2$

Terms containing $y^2$: $-15xy^2$, $7y^2$

Coefficient of $y^2$ in $-15xy^2$: $-15x$

Coefficient of $y^2$ in $7y^2$: $7$

Question 5. Classify into monomials, binomials and trinomials.

(i) 4y – 7z

(ii) y2

(iii) x + y – xy

(iv) 100

(v) ab – a – b

(vi) 5 – 3t

(vii) 4p2q – 4pq2

(viii) 7mn

(ix) z2 – 3z + 8

(x) a2 + b2

(xi) z2 + z

(xii) 1 + x + x2

Answer:

Classifying the given expressions:

(i) $4y – 7z$

Number of terms: 2

Classification: Binomial


(ii) $y^2$

Number of terms: 1

Classification: Monomial


(iii) $x + y – xy$

Number of terms: 3

Classification: Trinomial


(iv) $100$

Number of terms: 1

Classification: Monomial


(v) $ab – a – b$

Number of terms: 3

Classification: Trinomial


(vi) $5 – 3t$

Number of terms: 2

Classification: Binomial


(vii) $4p^2q – 4pq^2$

Number of terms: 2

Classification: Binomial


(viii) $7mn$

Number of terms: 1

Classification: Monomial


(ix) $z^2 – 3z + 8$

Number of terms: 3

Classification: Trinomial


(x) $a^2 + b^2$

Number of terms: 2

Classification: Binomial


(xi) $z^2 + z$

Number of terms: 2

Classification: Binomial


(xii) $1 + x + x^2$

Number of terms: 3

Classification: Trinomial

Question 6. State whether a given pair of terms is of like or unlike terms.

(i) 1 , 100

(ii) –7x , $\frac{5}{2}x$

(iii) – 29x , – 29y

(iv) 14xy , 42yx

(v) 4m2p , 4mp2

(vi) 12xz , 12x2z2

Answer:

(i) $1$, $100$

These are constant terms.

Classification: Like terms


(ii) $-7x$, $\frac{5}{2}x$

The variable part in both terms is $x$.

Classification: Like terms


(iii) $-29x$, $-29y$

The variable parts are $x$ and $y$, which are different.

Classification: Unlike terms


(iv) $14xy$, $42yx$

The variable parts are $xy$ and $yx$. Since multiplication is commutative, $xy$ is the same as $yx$.

Classification: Like terms


(v) $4m^2p$, $4mp^2$

The variable parts are $m^2p$ and $mp^2$. The powers of the variables are different.

Classification: Unlike terms


(vi) $12xz$, $12x^2z^2$

The variable parts are $xz$ and $x^2z^2$. The powers of the variables are different.

Classification: Unlike terms

Question 7. Identify like terms in the following:

(a) – xy2 , – 4yx2 , 8x2 , 2xy2 , 7y , – 11x2 , –100x , –11yx , 20x2y , – 6x2 , y , 2xy , 3x

(b) 10pq , 7p , 8q , – p2q2 , – 7qp , – 100q , – 23 , 12q2p2 , – 5p2 , 41 , 2405p , 78qp , 13p2q , qp2 , 701p2

Answer:

(a) Identify like terms in the following:

Like terms with variable part $xy^2$: $-xy^2$, $2xy^2$

Like terms with variable part $x^2y$: $-4yx^2$, $20x^2y$

Like terms with variable part $x^2$: $8x^2$, $-11x^2$, $-6x^2$

Like terms with variable part $y$: $7y$, $y$

Like terms with variable part $x$: $-100x$, $3x$

Like terms with variable part $xy$: $-11yx$, $2xy$


(b) Identify like terms in the following:

Like terms with variable part $pq$: $10pq$, $-7qp$, $78qp$

Like terms with variable part $p$: $7p$, $2405p$

Like terms with variable part $q$: $8q$, $-100q$

Like terms with variable part $p^2q^2$: $-p^2q^2$, $12q^2p^2$

Constant like terms: $-23$, $41$

Like terms with variable part $p^2$: $-5p^2$, $701p^2$

Like terms with variable part $p^2q$: $13p^2q$, $qp^2$



Example 4 to 6 (Before Exercise 10.2)

Example 4. Find the values of the following expressions for x = 2.

(i) x + 4

(ii) 4x – 3

(iii) 19 – 5x2

(iv) 100 – 10x3

Answer:

Given $x = 2$. We need to find the values of the following expressions:

(i) $x + 4$

Substitute $x=2$ into the expression:

$2 + 4$

Value of the expression is: $6$


(ii) $4x – 3$

Substitute $x=2$ into the expression:

$4(2) - 3$

$8 - 3$

Value of the expression is: $5$


(iii) $19 – 5x^2$

Substitute $x=2$ into the expression:

$19 - 5(2)^2$

$19 - 5(4)$

$19 - 20$

Value of the expression is: $-1$


(iv) $100 – 10x^3$

Substitute $x=2$ into the expression:

$100 - 10(2)^3$

$100 - 10(8)$

$100 - 80$

Value of the expression is: $20$

Example 5. Find the value of the following expressions when n = – 2.

(i) 5n – 2

(ii) 5n2 + 5n – 2

(iii) n3 + 5n2 + 5n – 2

Answer:

Given $n = -2$. We need to find the value of the following expressions:

(i) $5n - 2$

Substitute $n = -2$ into the expression:

$5(-2) - 2$

$-10 - 2$

Value of the expression is: $-12$


(ii) $5n^2 + 5n - 2$

Substitute $n = -2$ into the expression:

$5(-2)^2 + 5(-2) - 2$

$5(4) - 10 - 2$

$20 - 10 - 2$

$10 - 2$

Value of the expression is: $8$


(iii) $n^3 + 5n^2 + 5n - 2$

Substitute $n = -2$ into the expression:

$(-2)^3 + 5(-2)^2 + 5(-2) - 2$

$-8 + 5(4) - 10 - 2$

$-8 + 20 - 10 - 2$

$12 - 10 - 2$

$2 - 2$

Value of the expression is: $0$

Example 6. Find the value of the following expressions for a = 3, b = 2.

(i) a + b

(ii) 7a – 4b

(iii) a2 + 2ab + b2

(iv) a3 – b3

Answer:

Given $a = 3$ and $b = 2$. We need to find the value of the following expressions:

(i) $a + b$

Substitute $a=3$ and $b=2$ into the expression:

$3 + 2$

Value of the expression is: $5$


(ii) $7a – 4b$

Substitute $a=3$ and $b=2$ into the expression:

$7(3) - 4(2)$

$21 - 8$

Value of the expression is: $13$


(iii) $a^2 + 2ab + b^2$

Substitute $a=3$ and $b=2$ into the expression:

$(3)^2 + 2(3)(2) + (2)^2$

$9 + 2(6) + 4$

$9 + 12 + 4$

$21 + 4$

Value of the expression is: $25$


(iv) $a^3 – b^3$

Substitute $a=3$ and $b=2$ into the expression:

$(3)^3 - (2)^3$

$27 - 8$

Value of the expression is: $19$



Exercise 10.2

Question 1. If m = 2, find the value of:

(i) m – 2

(ii) 3m – 5

(iii) 9 – 5m

(iv) 3m2 – 2m – 7

(v) $\frac{5m}{2} - 4$

Answer:

Given $m = 2$. We need to find the value of the following expressions:


(i) $m – 2$

Substitute $m = 2$ into the expression:

$2 - 2$

Value of the expression is: $0$


(ii) $3m – 5$

Substitute $m = 2$ into the expression:

$3(2) - 5$

$6 - 5$

Value of the expression is: $1$


(iii) $9 – 5m$

Substitute $m = 2$ into the expression:

$9 - 5(2)$

$9 - 10$

Value of the expression is: $-1$


(iv) $3m^2 – 2m – 7$

Substitute $m = 2$ into the expression:

$3(2)^2 - 2(2) - 7$

$3(4) - 4 - 7$

$12 - 4 - 7$

$8 - 7$

Value of the expression is: $1$


(v) $\frac{5m}{2} - 4$

Substitute $m = 2$ into the expression:

$\frac{5(2)}{2} - 4$

$\frac{10}{2} - 4$

$5 - 4$

Value of the expression is: $1$

Question 2. If p = – 2, find the value of:

(i) 4p + 7

(ii) – 3p2 + 4p + 7

(iii) – 2p3 – 3p2 + 4p + 7

Answer:

Given $p = -2$. We need to find the value of the following expressions:


(i) $4p + 7$

Substitute $p = -2$ into the expression:

$4(-2) + 7$

$-8 + 7$

Value of the expression is: $-1$


(ii) $-3p^2 + 4p + 7$

Substitute $p = -2$ into the expression:

$-3(-2)^2 + 4(-2) + 7$

$-3(4) - 8 + 7$

$-12 - 8 + 7$

$-20 + 7$

Value of the expression is: $-13$


(iii) $-2p^3 – 3p^2 + 4p + 7$

Substitute $p = -2$ into the expression:

$-2(-2)^3 - 3(-2)^2 + 4(-2) + 7$

$-2(-8) - 3(4) - 8 + 7$

$16 - 12 - 8 + 7$

$4 - 8 + 7$

$-4 + 7$

Value of the expression is: $3$

Question 3. Find the value of the following expressions, when x = –1:

(i) 2x – 7

(ii) – x + 2

(iii) x2 + 2x + 1

(iv) 2x2 – x – 2

Answer:

Given $x = -1$. We need to find the value of the following expressions:


(i) $2x – 7$

Substitute $x = -1$ into the expression:

$2(-1) - 7$

$-2 - 7$

Value of the expression is: $-9$


(ii) $- x + 2$

Substitute $x = -1$ into the expression:

$-(-1) + 2$

$1 + 2$

Value of the expression is: $3$


(iii) $x^2 + 2x + 1$

Substitute $x = -1$ into the expression:

$(-1)^2 + 2(-1) + 1$

$1 - 2 + 1$

$-1 + 1$

Value of the expression is: $0$


(iv) $2x^2 – x – 2$

Substitute $x = -1$ into the expression:

$2(-1)^2 - (-1) - 2$

$2(1) + 1 - 2$

$2 + 1 - 2$

$3 - 2$

Value of the expression is: $1$

Question 4. If a = 2, b = – 2, find the value of:

(i) a2 + b2

(ii) a2 + ab + b2

(iii) a2 – b2

Answer:

Given $a = 2$ and $b = -2$. We need to find the value of the following expressions:


(i) $a^2 + b^2$

Substitute $a = 2$ and $b = -2$ into the expression:

$(2)^2 + (-2)^2$

$4 + 4$

Value of the expression is: $8$


(ii) $a^2 + ab + b^2$

Substitute $a = 2$ and $b = -2$ into the expression:

$(2)^2 + (2)(-2) + (-2)^2$

$4 + (-4) + 4$

$4 - 4 + 4$

$0 + 4$

Value of the expression is: $4$


(iii) $a^2 – b^2$

Substitute $a = 2$ and $b = -2$ into the expression:

$(2)^2 - (-2)^2$

$4 - (4)$

$4 - 4$

Value of the expression is: $0$

Question 5. When a = 0, b = – 1, find the value of the given expressions:

(i) 2a + 2b

(ii) 2a2 + b2 + 1

(iii) 2a2b + 2ab2 + ab

(iv) a2 + ab + 2

Answer:

Given $a = 0$ and $b = -1$. We need to find the value of the following expressions:


(i) $2a + 2b$

Substitute $a = 0$ and $b = -1$ into the expression:

$2(0) + 2(-1)$

$0 - 2$

Value of the expression is: $-2$


(ii) $2a^2 + b^2 + 1$

Substitute $a = 0$ and $b = -1$ into the expression:

$2(0)^2 + (-1)^2 + 1$

$2(0) + 1 + 1$

$0 + 1 + 1$

Value of the expression is: $2$


(iii) $2a^2b + 2ab^2 + ab$

Substitute $a = 0$ and $b = -1$ into the expression:

$2(0)^2(-1) + 2(0)(-1)^2 + (0)(-1)$

$2(0)(-1) + 2(0)(1) + 0$

$0 + 0 + 0$

Value of the expression is: $0$


(iv) $a^2 + ab + 2$

Substitute $a = 0$ and $b = -1$ into the expression:

$(0)^2 + (0)(-1) + 2$

$0 + 0 + 2$

Value of the expression is: $2$

Question 6. Simplify the expressions and find the value if x is equal to 2

(i) x + 7 + 4 (x – 5)

(ii) 3 (x + 2) + 5x – 7

(iii) 6x + 5 (x – 2)

(iv) 4(2x – 1) + 3x + 11

Answer:

Given $x = 2$. We need to simplify the expressions and find their values.


(i) $x + 7 + 4 (x – 5)$

Simplify the expression:

$x + 7 + 4x - 4 \times 5$

$x + 7 + 4x - 20$

Combine like terms:

$(x + 4x) + (7 - 20)$

$5x - 13$

Now, substitute $x = 2$ into the simplified expression:

$5(2) - 13$

$10 - 13$

Value of the expression is: $-3$


(ii) $3 (x + 2) + 5x – 7$

Simplify the expression:

$3x + 3 \times 2 + 5x - 7$

$3x + 6 + 5x - 7$

Combine like terms:

$(3x + 5x) + (6 - 7)$

$8x - 1$

Now, substitute $x = 2$ into the simplified expression:

$8(2) - 1$

$16 - 1$

Value of the expression is: $15$


(iii) $6x + 5 (x – 2)$

Simplify the expression:

$6x + 5x - 5 \times 2$

$6x + 5x - 10$

Combine like terms:

$(6x + 5x) - 10$

$11x - 10$

Now, substitute $x = 2$ into the simplified expression:

$11(2) - 10$

$22 - 10$

Value of the expression is: $12$


(iv) $4(2x – 1) + 3x + 11$

Simplify the expression:

$4 \times 2x - 4 \times 1 + 3x + 11$

$8x - 4 + 3x + 11$

Combine like terms:

$(8x + 3x) + (-4 + 11)$

$11x + 7$

Now, substitute $x = 2$ into the simplified expression:

$11(2) + 7$

$22 + 7$

Value of the expression is: $29$

Question 7. Simplify these expressions and find their values if x = 3, a = – 1, b = – 2.

(i) 3x – 5 – x + 9

(ii) 2 – 8x + 4x + 4

(iii) 3a + 5 – 8a + 1

(iv) 10 – 3b – 4 – 5b

(v) 2a – 2b – 4 – 5 + a

Answer:

Given $x = 3$, $a = -1$, and $b = -2$. We need to simplify the expressions and find their values.


(i) $3x – 5 – x + 9$

Simplify the expression:

$(3x - x) + (-5 + 9)$

$2x + 4$

Now, substitute $x = 3$ into the simplified expression:

$2(3) + 4$

$6 + 4$

Value of the expression is: $10$


(ii) $2 – 8x + 4x + 4$

Simplify the expression:

$(-8x + 4x) + (2 + 4)$

$-4x + 6$

Now, substitute $x = 3$ into the simplified expression:

$-4(3) + 6$

$-12 + 6$

Value of the expression is: $-6$


(iii) $3a + 5 – 8a + 1$

Simplify the expression:

$(3a - 8a) + (5 + 1)$

$-5a + 6$

Now, substitute $a = -1$ into the simplified expression:

$-5(-1) + 6$

$5 + 6$

Value of the expression is: $11$


(iv) $10 – 3b – 4 – 5b$

Simplify the expression:

$(-3b - 5b) + (10 - 4)$

$-8b + 6$

Now, substitute $b = -2$ into the simplified expression:

$-8(-2) + 6$

$16 + 6$

Value of the expression is: $22$


(v) $2a – 2b – 4 – 5 + a$

Simplify the expression:

$(2a + a) + (-2b) + (-4 - 5)$

$3a - 2b - 9$

Now, substitute $a = -1$ and $b = -2$ into the simplified expression:

$3(-1) - 2(-2) - 9$

$-3 + 4 - 9$

$1 - 9$

Value of the expression is: $-8$

Question 8.

(i) If z = 10, find the value of z3 – 3(z – 10).

(ii) If p = – 10, find the value of p2 – 2p – 100

Answer:

(i) If $z = 10$, find the value of $z^3 – 3(z – 10)$.

Given expression: $z^3 – 3(z – 10)$

Given $z = 10$.

Substitute $z = 10$ into the expression:

$(10)^3 - 3(10 - 10)$

$1000 - 3(0)$

$1000 - 0$

Value of the expression is: $1000$


(ii) If $p = – 10$, find the value of $p^2 – 2p – 100$.

Given expression: $p^2 – 2p – 100$

Given $p = -10$.

Substitute $p = -10$ into the expression:

$(-10)^2 - 2(-10) - 100$

$100 - (-20) - 100$

$100 + 20 - 100$

$120 - 100$

Value of the expression is: $20$

Question 9. What should be the value of a if the value of 2x2 + x – a equals to 5, when x = 0?

Answer:

Given expression: $2x^2 + x – a$


We are given that the value of the expression is $5$ when $x = 0$.


Substitute $x = 0$ into the expression:

$2(0)^2 + (0) – a$

$2(0) + 0 – a$

$0 + 0 – a$

$-a$


Now, we set this equal to the given value, $5$:

$-a = 5$

To find the value of $a$, multiply both sides of the equation by $-1$:

$a = -5$


Therefore, the value of $a$ should be $-5$.

Question 10. Simplify the expression and find its value when a = 5 and b = – 3.

2(a2 + ab) + 3 – ab

Answer:

Given expression: $2(a^2 + ab) + 3 – ab$

Given values: $a = 5$ and $b = -3$.


First, simplify the expression:

$2(a^2 + ab) + 3 – ab$

$2a^2 + 2ab + 3 – ab$

Combine like terms:

$2a^2 + (2ab – ab) + 3$

$2a^2 + ab + 3$


Now, substitute the given values $a = 5$ and $b = -3$ into the simplified expression:

$2(5)^2 + (5)(-3) + 3$

$2(25) + (-15) + 3$

$50 - 15 + 3$

$35 + 3$

The value of the expression is: $38$