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Increasing and Decreasing Functions: Definitions Test for Monotonicity using First Derivative Finding Intervals of Increase and Decrease
Increasing /Decreasing Functions (Applied Maths)


Applications of Derivatives: Monotonicity (Increasing/Decreasing Functions)



Increasing and Decreasing Functions: Definitions

The concept of a function being increasing or decreasing, collectively known as monotonicity, describes the overall trend of the function's output values as the input variable increases. This is a fundamental property used in analyzing the behavior and shape of a function's graph.

Definitions on an Interval $I$

Let $f$ be a real-valued function defined on an interval $I$ of real numbers. The interval $I$ can be any type of interval: open $(a, b)$, closed $[a, b]$, half-open $[a, b)$ or $(a, b]$, or infinite $(-\infty, b)$, $(a, \infty)$, $(-\infty, \infty)$.

The definitions of increasing and decreasing functions are based on comparing function values for different inputs within the interval.

  1. Strictly Increasing Function: A function $f$ is said to be strictly increasing on the interval $I$ if for any two distinct numbers $x_1$ and $x_2$ chosen from $I$, whenever $x_1$ is less than $x_2$, the corresponding function value $f(x_1)$ is strictly less than $f(x_2)$.

    Formally: $f$ is strictly increasing on $I$ if $\forall x_1, x_2 \in I, x_1 < x_2 \implies f(x_1) < f(x_2)$.

    Interpretation: As you move from left to right across the interval $I$ on the x-axis (meaning $x$ is increasing), the graph of the function $y=f(x)$ is always climbing upwards. There are no flat spots or downward movements in the graph over this interval.

    Graph of a strictly increasing function

    Example: $f(x) = x^3$ is strictly increasing on $(-\infty, \infty)$. If $x_1 < x_2$, then $x_1^3 < x_2^3$.

  2. Increasing Function (Non-Decreasing Function): A function $f$ is said to be increasing (or non-decreasing) on the interval $I$ if for any two distinct numbers $x_1$ and $x_2$ chosen from $I$, whenever $x_1$ is less than $x_2$, the corresponding function value $f(x_1)$ is less than or equal to $f(x_2)$.

    Formally: $f$ is increasing on $I$ if $\forall x_1, x_2 \in I, x_1 < x_2 \implies f(x_1) \le f(x_2)$.

    Interpretation: As you move from left to right across the interval $I$, the graph of the function is climbing upwards or staying flat. It never moves downwards. A strictly increasing function is a special case of an increasing function.

    Graph of an increasing (non-decreasing) function

    Example: $f(x) = \begin{cases} x & , & x \le 0 \\ 0 & , & 0 < x \le 1 \\ x-1 & , & x > 1 \end{cases}$ is increasing on $(-\infty, \infty)$. It is strictly increasing on $(-\infty, 0]$ and $(1, \infty)$, and constant (thus also increasing and decreasing by the non-strict definition) on $(0, 1]$.

  3. Strictly Decreasing Function: A function $f$ is said to be strictly decreasing on the interval $I$ if for any two distinct numbers $x_1$ and $x_2$ chosen from $I$, whenever $x_1$ is less than $x_2$, the corresponding function value $f(x_1)$ is strictly greater than $f(x_2)$.

    Formally: $f$ is strictly decreasing on $I$ if $\forall x_1, x_2 \in I, x_1 < x_2 \implies f(x_1) > f(x_2)$.

    Interpretation: As you move from left to right across the interval $I$, the graph of the function is always falling downwards. There are no flat spots or upward movements.

    Graph of a strictly decreasing function

    Example: $f(x) = -x$ is strictly decreasing on $(-\infty, \infty)$. If $x_1 < x_2$, then $-x_1 > -x_2$.

  4. Decreasing Function (Non-Increasing Function): A function $f$ is said to be decreasing (or non-increasing) on the interval $I$ if for any two distinct numbers $x_1$ and $x_2$ chosen from $I$, whenever $x_1$ is less than $x_2$, the corresponding function value $f(x_1)$ is greater than or equal to $f(x_2)$.

    Formally: $f$ is decreasing on $I$ if $\forall x_1, x_2 \in I, x_1 < x_2 \implies f(x_1) \ge f(x_2)$.

    Interpretation: As you move from left to right across the interval $I$, the graph of the function is falling downwards or staying flat. It never moves upwards. A strictly decreasing function is a special case of a decreasing function.

    Graph of a decreasing (non-increasing) function

    Example: $f(x) = \begin{cases} -x & , & x \le 0 \\ 0 & , & 0 < x \le 1 \\ -(x-1) & , & x > 1 \end{cases}$ is decreasing on $(-\infty, \infty)$. It is strictly decreasing on $(-\infty, 0]$ and $(1, \infty)$, and constant (thus also increasing and decreasing by the non-strict definition) on $(0, 1]$.

  5. Monotonic Function: A function $f$ is said to be monotonic on an interval $I$ if it is either increasing on $I$ or decreasing on $I$. If it is either strictly increasing or strictly decreasing on $I$, it is called strictly monotonic.

    Monotonic functions are particularly important because a strictly monotonic function on an interval has a unique inverse function over that interval.




Applications of Derivatives: Test for Monotonicity using First Derivative

The definitions of increasing and decreasing functions describe the behavior based on comparing function values. However, using the first derivative provides a much more efficient method to determine intervals of monotonicity, especially for functions defined by formulas.

The connection between the derivative and monotonicity lies in the geometric interpretation: the derivative $f'(x)$ at a point $x$ gives the slope of the tangent line to the graph of $f(x)$ at that point. Intuitively, if the tangent line at every point in an interval has a positive slope, the function must be increasing over that interval. Similarly, if the tangent line always has a negative slope, the function must be decreasing.

The formal relationship is established by the Mean Value Theorem. If $f'(x) > 0$ for all $x$ in $(a, b)$, consider any $x_1, x_2 \in [a, b]$ with $x_1 < x_2$. By the MVT, there exists a $c \in (x_1, x_2)$ such that $\frac{f(x_2) - f(x_1)}{x_2 - x_1} = f'(c)$. Since $x_1 < x_2$, $x_2 - x_1 > 0$. Also, $c \in (x_1, x_2) \subseteq (a, b)$, so $f'(c) > 0$. Thus, $\frac{f(x_2) - f(x_1)}{x_2 - x_1} > 0$. Since the denominator is positive, the numerator $f(x_2) - f(x_1)$ must be positive, meaning $f(x_2) > f(x_1)$. This proves that $f$ is strictly increasing on $[a, b]$. Similar arguments hold for the other cases.

First Derivative Test for Monotonicity

Let $f$ be a function that is continuous on a closed interval $[a, b]$ and differentiable on the open interval $(a, b)$. The sign of the first derivative $f'(x)$ on the open interval $(a, b)$ determines the monotonicity of $f(x)$ on the entire closed interval $[a, b]$.

  1. If $f'(x) > 0$ for all $x$ in the open interval $(a, b)$, then the function $f$ is strictly increasing on the closed interval $[a, b]$.

    Explanation: A positive derivative indicates a positive slope of the tangent, meaning the function is locally increasing at every point. Over an interval, this leads to a strictly increasing trend.

  2. If $f'(x) < 0$ for all $x$ in the open interval $(a, b)$, then the function $f$ is strictly decreasing on the closed interval $[a, b]$.

    Explanation: A negative derivative indicates a negative slope of the tangent, meaning the function is locally decreasing at every point. Over an interval, this leads to a strictly decreasing trend.

  3. If $f'(x) = 0$ for all $x$ in the open interval $(a, b)$, then the function $f$ is constant on the closed interval $[a, b]$.

    Explanation: A zero derivative indicates a zero slope of the tangent (horizontal line). If the slope is always horizontal, the function value does not change over the interval.

Important Notes and Extensions:

The First Derivative Test for Monotonicity is a fundamental application of differentiation, enabling the detailed analysis of a function's behavior and serving as a cornerstone for finding local extrema.



Finding Intervals of Increase and Decrease

Using the First Derivative Test for Monotonicity, we can develop a systematic procedure to determine the intervals on which a function $f(x)$ is strictly increasing or strictly decreasing. This process involves finding the points where the derivative might change sign and then testing the sign of the derivative in the intervals defined by these points.

Steps for Finding Intervals of Monotonicity:

  1. Determine the Domain of the Function: Identify the set of all possible input values $x$ for which $f(x)$ is defined. This is the overall region on the number line where the function exists. Consider any restrictions from square roots of negative numbers, denominators being zero, logarithms of non-positive numbers, etc.
  2. Find the First Derivative: Calculate the derivative $f'(x)$ using the appropriate differentiation rules.
  3. Find the Critical Points of $f(x)$: Critical points are the points in the domain of the function where the derivative is either zero or undefined. These are the only points where the function's graph can potentially change from increasing to decreasing or vice versa.
    • Set $f'(x) = 0$ and solve for $x$. The solutions are critical points where the tangent line is horizontal.
    • Find the values of $x$ where $f'(x)$ is undefined. These could occur at points where the original function has sharp corners, cusps, or vertical tangents. Remember that $x$ must be in the domain of the original function $f(x)$ to be a critical point.
  4. Create Intervals on the Number Line: Use the critical points found in Step 3 (and any points where the original function $f(x)$ is discontinuous or undefined) to divide the domain of $f$ into a series of open intervals. Arrange these points in increasing order on a number line, and these points serve as boundary markers for the intervals.
  5. Test the Sign of $f'(x)$ within Each Interval: Choose a single convenient test value $x_{test}$ within each open interval created in Step 4. Evaluate the sign of the derivative $f'(x_{test})$ at this test value. The sign of $f'(x)$ will be the same for all values of $x$ within that entire open interval because $f'(x)$ can only change sign at critical points or points of discontinuity.
  6. State Conclusions about Monotonicity: Based on the sign of $f'(x)$ in each interval:
    • If $f'(x) > 0$ for all $x$ in an open interval, then $f(x)$ is strictly increasing on that open interval.
    • If $f'(x) < 0$ for all $x$ in an open interval, then $f(x)$ is strictly decreasing on that open interval.
  7. Write the Final Answer using Closed Intervals (Optional but Common): For functions that are continuous at the critical points, the intervals of strict monotonicity are often extended to include the critical points themselves, stating where the function is "increasing" or "decreasing" (using the non-strict definitions $f'(x) \ge 0$ or $f'(x) \le 0$). If $f$ is continuous at $x=c$ where $f'(c)=0$, and the function is strictly increasing to the left of $c$ and strictly increasing to the right of $c$, then $f$ is strictly increasing over the combined interval including $c$. If it changes direction at $c$, then $c$ is included in the closed interval for increasing behavior ending at $c$, and the closed interval for decreasing behavior starting at $c$ (or vice versa). Always check the continuity of $f$ at the endpoints of the closed interval you state.

This process provides a clear roadmap for identifying where a function's graph is rising or falling.


Example 1. Find the intervals on which the function $f(x) = 2x^3 - 3x^2 - 36x + 7$ is strictly increasing or strictly decreasing.

Answer:

Step 1: Find the Domain.

The function $f(x) = 2x^3 - 3x^2 - 36x + 7$ is a polynomial. Polynomial functions are defined for all real numbers.

Domain of $f$: $(-\infty, \infty)$.

Step 2: Find the First Derivative.

Differentiate $f(x)$ with respect to $x$:

"$f'(x) = \frac{d}{dx}(2x^3 - 3x^2 - 36x + 7)$"

Using differentiation rules:

"$f'(x) = 2(3x^2) - 3(2x) - 36(1) + 0$"

"$f'(x) = 6x^2 - 6x - 36$"

Step 3: Find Critical Points.

Critical points occur where $f'(x) = 0$ or $f'(x)$ is undefined.

$f'(x) = 6x^2 - 6x - 36$ is a polynomial, which is defined for all real numbers. So, there are no critical points where the derivative is undefined.

Set $f'(x) = 0$ and solve for $x$:

"$6x^2 - 6x - 36 = 0$"

[Set $f'(x)=0$]

Divide the equation by 6:

"$x^2 - x - 6 = 0$"

Factor the quadratic expression:

"$(x - 3)(x + 2) = 0$"

This gives two solutions:

"$x - 3 = 0 \implies x = 3$"

"$x + 2 = 0 \implies x = -2$"

The critical points are $x = -2$ and $x = 3$.

Step 4: Create Intervals.

The critical points $x = -2$ and $x = 3$ divide the domain $(-\infty, \infty)$ into three open intervals:

Interval 1: $(-\infty, -2)$

Interval 2: $(-2, 3)$

Interval 3: $(3, \infty)$

Step 5: Test the Sign of $f'(x)$ in each Interval.

We choose a test value within each interval and evaluate the sign of $f'(x) = 6x^2 - 6x - 36$ or the factored form $f'(x) = 6(x-3)(x+2)$.

  • Interval $(-\infty, -2)$: Choose a test value, e.g., $x = -3$.

    $f'(-3) = 6((-3)-3)((-3)+2) = 6(-6)(-1) = 36$.

    Since $f'(-3) = 36 > 0$, the derivative is positive on this interval.

  • Interval $(-2, 3)$: Choose a test value, e.g., $x = 0$.

    $f'(0) = 6((0)-3)((0)+2) = 6(-3)(2) = -36$.

    Since $f'(0) = -36 < 0$, the derivative is negative on this interval.

  • Interval $(3, \infty)$: Choose a test value, e.g., $x = 4$.

    $f'(4) = 6((4)-3)((4)+2) = 6(1)(6) = 36$.

    Since $f'(4) = 36 > 0$, the derivative is positive on this interval.

Step 6: State Conclusions about Monotonicity.

Based on the First Derivative Test:

  • Since $f'(x) > 0$ on $(-\infty, -2)$, the function $f(x)$ is strictly increasing on $(-\infty, -2)$.
  • Since $f'(x) < 0$ on $(-2, 3)$, the function $f(x)$ is strictly decreasing on $(-2, 3)$.
  • Since $f'(x) > 0$ on $(3, \infty)$, the function $f(x)$ is strictly increasing on $(3, \infty)$.

Summary of Intervals:

The function $f(x)$ is strictly increasing on the intervals $(-\infty, -2)$ and $(3, \infty)$.

The function $f(x)$ is strictly decreasing on the interval $(-2, 3)$.

(Since $f(x)$ is continuous at the critical points $x=-2$ and $x=3$, we could also state that $f(x)$ is increasing on $(-\infty, -2]$ and $[3, \infty)$, and decreasing on $[-2, 3]$ using the non-strict definitions of increasing/decreasing).



Increasing /Decreasing Functions (Applied Maths)

In applied mathematics, science, and engineering, functions are used to model real-world phenomena. Understanding where these functions are increasing or decreasing provides crucial insights into the behavior of the system being modeled. Analyzing the sign of the first derivative allows us to interpret the dynamic behavior of quantities such as position, velocity, cost, revenue, population size, etc.

Interpretation and Applications in Applied Contexts

The sign of the derivative $f'(x)$ tells us whether the quantity represented by $f(x)$ is growing or shrinking as $x$ increases. This has direct practical implications:

In applied problems, after setting up a function to model a situation, finding its derivative and analyzing its sign over the relevant domain (often restricted to physically meaningful values, like non-negative time or quantity) is a crucial step in understanding the dynamic behavior of the modeled phenomenon, such as when it's growing, shrinking, speeding up, slowing down, or reaching an optimal state.