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Cartesian Coordinate System in Three Dimensions (Axes, Planes, Octants) Coordinates of a Point in Space Distance from Coordinate Planes and Axes


Introduction to Three-Dimensional Geometry



Cartesian Coordinate System in Three Dimensions (Axes, Planes, Octants)

Expanding upon the concept of locating points in a two-dimensional plane using a pair of perpendicular axes, the Cartesian Coordinate System in Three Dimensions provides a framework for specifying the position of any point in space. This system uses three mutually perpendicular axes that intersect at a single origin.

Coordinate Axes

3D Cartesian Coordinate System

Coordinate Planes

The three coordinate axes, when taken two at a time, define three mutually perpendicular planes. These planes are called the coordinate planes, and they effectively divide the 3D space into different regions.

These three planes intersect pairwise along the coordinate axes (XY and XZ intersect along the x-axis, XY and YZ intersect along the y-axis, and XZ and YZ intersect along the z-axis). All three planes intersect at the origin $O(0, 0, 0)$.

Coordinate Planes in 3D space

Octants

The three coordinate planes ($z=0$, $x=0$, and $y=0$) divide the entire three-dimensional space into eight distinct regions. These regions are analogous to the quadrants in a 2D system and are called octants (from the Latin word "octo" meaning eight).

Each octant is uniquely defined by the combination of the signs (+ or –) of the x, y, and z coordinates of the points that lie within that region. The origin and the points lying on the coordinate axes and planes are not considered to be within any octant.

The signs of the coordinates in each octant, following a common numbering convention (although other conventions exist), are as follows:

Octant x-coordinate Sign y-coordinate Sign z-coordinate Sign
I + + +
II + +
III +
IV + +
V + +
VI +
VII
VIII +

The first octant (Octant I) is the region where all three coordinates ($x, y, z$) are positive ($x>0, y>0, z>0$). The other octants are numbered based on the signs of the x and y coordinates relative to the first quadrant in the XY-plane (when viewed from above, i.e., from the positive z-axis), extended into the regions where z is positive (Octants I to IV) and where z is negative (Octants V to VIII).


3D Cartesian System (Summary)

Axes:

  • Three mutually perpendicular axes: x-axis, y-axis, z-axis.
  • Intersection point: Origin $O(0, 0, 0)$.
  • Orientation: Usually right-handed system.

Planes:

  • XY-plane (contains x and y axes): Equation $z = 0$.
  • YZ-plane (contains y and z axes): Equation $x = 0$.
  • XZ-plane (contains x and z axes): Equation $y = 0$.

Octants:

  • Eight regions space divided by coordinate planes.
  • Characterized by signs of $(x, y, z)$ coordinates.
  • Octant I: $(+, +, +)$.

Coordinates:

Any point in space is uniquely identified by an ordered triplet $(x, y, z)$.



Coordinates of a Point in Space

In the three-dimensional Cartesian coordinate system, the position of any point in space is uniquely determined by an ordered triplet of real numbers. These numbers are the point's coordinates and represent its directed distances from the three coordinate planes.

For a point $P$ in space, its coordinates are written as $(x, y, z)$.

Coordinates of a point P(x, y, z) in 3D space

To visualize the location of a point $P(x, y, z)$:

Start at the origin $O(0, 0, 0)$.

Move $x$ units along the x-axis (positive direction if $x>0$, negative if $x<0$). Let's call this point $P_x(x, 0, 0)$.

From $P_x$, move $y$ units parallel to the y-axis (positive direction if $y>0$, negative if $y<0$). This takes you to a point in the XY-plane, $P_{xy}(x, y, 0)$.

From $P_{xy}$, move $z$ units parallel to the z-axis (positive direction if $z>0$, negative if $z<0$). The endpoint is the point $P(x, y, z)$.

Alternatively, you can imagine forming a rectangular box with one vertex at the origin and the opposite vertex at $P(x, y, z)$, such that the edges of the box are parallel to the coordinate axes. The lengths of the edges along the x, y, and z directions correspond to $|x|, |y|, |z|$.


Coordinates of Points on Axes and Planes

Points that lie on the coordinate axes or in the coordinate planes have one or two of their coordinates equal to zero:


Example 1. In which octant or on which plane/axis do the following points lie?

(a) (2, 3, 4)     (b) (-1, 2, 5)     (c) (3, -4, -1)     (d) (0, 5, -2)     (e) (7, 0, 0)     (f) (-2, -3, 6)

Answer:

We determine the location based on the signs of the non-zero coordinates or which coordinates are zero.

  • (a) (2, 3, 4): The coordinates are $x=2, y=3, z=4$. All are positive ($+, +, +$). This point lies in Octant I.

  • (b) (-1, 2, 5): The coordinates are $x=-1, y=2, z=5$. The signs are (–, +, +). This point lies in Octant II.

  • (c) (3, -4, -1): The coordinates are $x=3, y=-4, z=-1$. The signs are (+, –, –). This point lies in Octant VIII.

  • (d) (0, 5, -2): The coordinates are $x=0, y=5, z=-2$. Since the x-coordinate is 0, the point lies in the plane where $x=0$. This is the YZ-plane.

  • (e) (7, 0, 0): The coordinates are $x=7, y=0, z=0$. Since the y and z coordinates are 0, the point lies on the intersection of the XZ-plane ($y=0$) and the XY-plane ($z=0$), which is the x-axis.

  • (f) (-2, -3, 6): The coordinates are $x=-2, y=-3, z=6$. The signs are (–, –, +). This point lies in Octant III.


Coordinates in 3D Space (Summary)

Point Coordinates:

A point $P$ is uniquely identified by an ordered triplet $(x, y, z)$.

  • $x$: directed distance from YZ-plane ($x=0$).
  • $y$: directed distance from XZ-plane ($y=0$).
  • $z$: directed distance from XY-plane ($z=0$).

Points on Axes:

  • x-axis: $(x, 0, 0)$.
  • y-axis: $(0, y, 0)$.
  • z-axis: $(0, 0, z)$.
  • Origin: $(0, 0, 0)$.

Points on Planes:

  • XY-plane: $(x, y, 0)$ (Equation $z=0$).
  • YZ-plane: $(0, y, z)$ (Equation $x=0$).
  • XZ-plane: $(x, 0, z)$ (Equation $y=0$).

Location by Signs:

Non-zero coordinates determine the octant based on their signs.



Distance from Coordinate Planes and Axes

In the 3D Cartesian system, the coordinates of a point $P(x, y, z)$ not only specify its unique location but also directly provide information about its distances from the coordinate planes and axes. The distances considered here are the perpendicular distances, as the shortest distance from a point to a plane or a line is along the perpendicular segment.

Distance from Coordinate Planes

The coordinate planes are the YZ-plane ($x=0$), the XZ-plane ($y=0$), and the XY-plane ($z=0$). The coordinates of a point $P(x, y, z)$ are defined as its signed perpendicular distances from these planes. The actual (unsigned) distance is the absolute value of the corresponding coordinate.

For a point $P(x, y, z)$:


Distance from Coordinate Axes

The distance of a point $P(x, y, z)$ from a coordinate axis (x-axis, y-axis, or z-axis) is the length of the perpendicular segment from the point to that axis. The foot of this perpendicular on the axis is the point on the axis closest to $P$.


Summary Table: Distances for Point P(x, y, z)

Distance From Geometric Entity Equation(s) of the Entity Distance Formula
YZ-plane Coordinate Plane $x = 0$ $|x|$
XZ-plane Coordinate Plane $y = 0$ $|y|$
XY-plane Coordinate Plane $z = 0$ $|z|$
x-axis Coordinate Axis $y=0$ and $z=0$ $\sqrt{y^2 + z^2}$
y-axis Coordinate Axis $x=0$ and $z=0$ $\sqrt{x^2 + z^2}$
z-axis Coordinate Axis $x=0$ and $y=0$ $\sqrt{x^2 + y^2}$

Example 1. Find the perpendicular distances of the point P(3, -4, 5) from the coordinate planes and coordinate axes.

Answer:

Given the coordinates of the point $P(x, y, z) = (3, -4, 5)$. So, $x = 3$, $y = -4$, and $z = 5$.

Distances from Coordinate Planes:

  • Distance from the YZ-plane ($x=0$) is the absolute value of the x-coordinate: $|x| = |3| = \mathbf{3 \text{ units}}$.
  • Distance from the XZ-plane ($y=0$) is the absolute value of the y-coordinate: $|y| = |-4| = \mathbf{4 \text{ units}}$.
  • Distance from the XY-plane ($z=0$) is the absolute value of the z-coordinate: $|z| = |5| = \mathbf{5 \text{ units}}$.

Distances from Coordinate Axes:

  • Distance from the x-axis is $\sqrt{y^2 + z^2}$. Substitute $y=-4$ and $z=5$:

    Distance from x-axis $= \sqrt{(-4)^2 + 5^2} = \sqrt{16 + 25} = \sqrt{41}$.

    The distance from the x-axis is $\mathbf{\sqrt{41} \text{ units}}$.

  • Distance from the y-axis is $\sqrt{x^2 + z^2}$. Substitute $x=3$ and $z=5$:

    Distance from y-axis $= \sqrt{3^2 + 5^2} = \sqrt{9 + 25} = \sqrt{34}$.

    The distance from the y-axis is $\mathbf{\sqrt{34} \text{ units}}$.

  • Distance from the z-axis is $\sqrt{x^2 + y^2}$. Substitute $x=3$ and $y=-4$:

    Distance from z-axis $= \sqrt{3^2 + (-4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5$.

    The distance from the z-axis is $\mathbf{5 \text{ units}}$.


Distances in 3D (Summary for Competitive Exams)

Point: $P(x, y, z)$

Distances from Planes:

  • YZ-plane ($x=0$): $|x|$
  • XZ-plane ($y=0$): $|y|$
  • XY-plane ($z=0$): $|z|$

Distances from Axes:

  • x-axis: $\sqrt{y^2 + z^2}$
  • y-axis: $\sqrt{x^2 + z^2}$
  • z-axis: $\sqrt{x^2 + y^2}$

Key Idea:

Distance from a plane = absolute value of the coordinate perpendicular to that plane.

Distance from an axis = distance to the projection of the point onto that axis = square root of sum of squares of the other two coordinates.