Matching Items MCQs for Sub-Topics of Topic 7: Mensuration
Introduction to Mensuration: Perimeter and Area Concepts
Question 1. Match the fundamental concept with its description.
(i) Mensuration
(ii) Perimeter
(iii) Area
(iv) Volume
(a) Measure of the capacity of a 3D object
(b) Measure of the boundary of a 2D shape
(c) Measure of the surface enclosed by a 2D shape
(d) Measurement of geometric figures
Answer:
Question 2. Match the measurement type with the appropriate unit.
(i) Length
(ii) Area
(iii) Volume
(iv) Circumference
(a) $\text{m}^3$
(b) $\text{cm}^2$
(c) $\text{km}$
(d) $\text{mm}$
Answer:
Question 3. Match the concept with the figure property it measures.
(i) Perimeter
(ii) Area
(iii) Side
(iv) Capacity
(a) Amount of surface
(b) One-dimensional measure
(c) Boundary length
(d) Space inside a container
Answer:
Question 4. Match the scenario with the relevant concept.
(i) Cost of painting a wall
(ii) Cost of buying wire for a fence
(iii) Cost of filling a pool
(iv) Cost of tiling a roof
(a) Volume
(b) Surface Area (on solid)
(c) Perimeter
(d) Area (on plane)
Answer:
Question 5. Match the shape with the primary concept used for its measurement in this introduction.
(i) Square
(ii) Cube
(iii) Triangle
(iv) Sphere
(a) Volume/Surface Area
(b) Perimeter/Area
(c) Perimeter/Area
(d) Volume/Surface Area
Answer:
Perimeter of Various Plane Figures
Question 1. Match the geometric figure with its perimeter calculation method.
(i) Polygon
(ii) Square
(iii) Rectangle
(iv) Equilateral Triangle
(a) Sum of lengths of all sides
(b) $4 \times$ side length
(c) $2 \times$ (length + width)
(d) $3 \times$ side length
Answer:
Question 2. Match the given dimensions with the perimeter.
(i) Square, side 8 cm
(ii) Rectangle, length 10 m, width 5 m
(iii) Triangle, sides 6 cm, 8 cm, 10 cm
(iv) Parallelogram, adjacent sides 7 m, 4 m
(a) 22 m
(b) 24 cm
(c) 32 cm
(d) 30 m
Answer:
Question 3. Match the statement with the consequence for perimeter.
(i) Doubling the side of a square
(ii) Doubling the length and width of a rectangle
(iii) Halving the side of an equilateral triangle
(iv) Keeping perimeter constant but changing shape from square to rectangle
(a) Perimeter is halved
(b) Perimeter remains unchanged (potentially)
(c) Perimeter is doubled
(d) Perimeter is doubled
Answer:
Question 4. Match the term related to perimeter with its definition.
(i) Boundary
(ii) Regular polygon
(iii) Circumference
(iv) Semi-perimeter
(a) Half of the perimeter of a triangle
(b) The perimeter of a circle
(c) All sides and angles are equal
(d) The outer limit of a shape
Answer:
Question 5. Match the figure description with the perimeter formula.
(i) Square with side $s$
(ii) Rectangle with length $l$ and width $w$
(iii) Triangle with sides $a, b, c$
(iv) Parallelogram with adjacent sides $p, q$
(a) $2(p+q)$
(b) $a+b+c$
(c) $2(l+w)$
(d) $4s$
Answer:
Area of Basic Plane Figures
Question 1. Match the figure with its area formula (using standard notations: $s$ for side, $l$ for length, $w$ for width, $b$ for base, $h$ for height, $a, b$ for parallel sides of trapezium).
(i) Square
(ii) Rectangle
(iii) Triangle
(iv) Parallelogram
(a) $b \times h$
(b) $s^2$
(c) $l \times w$
(d) $\frac{1}{2} \times b \times h$
Answer:
Question 2. Match the given dimensions with the area.
(i) Square, side 7 cm
(ii) Rectangle, length 12 m, width 8 m
(iii) Triangle, base 10 cm, height 6 cm
(iv) Parallelogram, base 9 m, height 5 m
(a) $45\ \text{m}^2$
(b) $96\ \text{m}^2$
(c) $49\ \text{cm}^2$
(d) $30\ \text{cm}^2$
Answer:
Question 3. Match the statement with the consequence for area.
(i) Doubling the side of a square
(ii) Doubling the length and width of a rectangle
(iii) Doubling the base of a triangle while keeping height same
(iv) Halving the base and height of a parallelogram
(a) Area is halved
(b) Area becomes four times
(c) Area is doubled
(d) Area becomes one-fourth
Answer:
Question 4. Match the figure property with the correct area unit.
(i) Area of a stamp
(ii) Area of a room floor
(iii) Area of a small field
(iv) Area of a country
(a) $\text{km}^2$
(b) $\text{m}^2$
(c) $\text{cm}^2$
(d) Hectare
Answer:
Question 5. Match the related area formulas/concepts.
(i) Area of a square
(ii) Area of a rectangle
(iii) Area of a right triangle
(iv) Area of a parallelogram
(a) base $\times$ height
(b) $\frac{1}{2} \times$ product of perpendicular sides
(c) side $\times$ side
(d) length $\times$ width
Answer:
Area of Triangles using Heron's Formula
Question 1. Match the term used in Heron's formula with its meaning.
(i) $a, b, c$
(ii) $s$
(iii) $\sqrt{s(s-a)(s-b)(s-c)}$
(iv) $a+b+c$
(a) Perimeter of the triangle
(b) Area of the triangle
(c) Lengths of the sides
(d) Semi-perimeter of the triangle
Answer:
Question 2. Match the triangle type with the calculation that might use Heron's formula effectively.
(i) Scalene Triangle
(ii) Equilateral Triangle
(iii) Isosceles Triangle
(iv) Right-angled Triangle
(a) $\sqrt{s(s-a)(s-a)(s-c)}$
(b) $\sqrt{s(s-a)(s-b)(s-c)}$
(c) $\sqrt{s(s-a)(s-a)(s-a)}$
(d) Can be used, but base $\times$ height is simpler
Answer:
Question 3. Match the set of side lengths with the correct semi-perimeter.
(i) 6, 8, 10
(ii) 5, 12, 13
(iii) 7, 15, 20
(iv) 10, 10, 16
(a) 18
(b) 16
(c) 12
(d) 15
Answer:
Question 4. Match the triangle side lengths with the calculated area using Heron's formula.
(i) 3, 4, 5
(ii) 5, 12, 13
(iii) 7, 8, 9
(iv) 13, 14, 15
(a) 6
(b) 84
(c) $12\sqrt{5}$
(d) 30
Answer:
Question 5. Match the specific triangle case with its simplified area formula (derived from Heron's or other methods).
(i) Equilateral triangle, side $a$
(ii) Right triangle, legs $b, h$
(iii) Triangle, base $b$, height $h$
(iv) Isosceles right triangle, leg $a$
(a) $\frac{1}{2} \times b \times h$
(b) $\frac{\sqrt{3}}{4}a^2$
(c) $\frac{1}{2}a^2$
(d) $\frac{1}{2} \times b \times h$
Answer:
Area of Quadrilaterals and Polygons (Advanced)
Question 1. Match the quadrilateral with its area formula.
(i) Rhombus
(ii) Kite
(iii) General Quadrilateral (with diagonal $d$, perpendiculars $h_1, h_2$)
(iv) Trapezium (parallel sides $a, b$, height $h$)
(a) $\frac{1}{2} d_1 d_2$
(b) $\frac{1}{2} (a+b)h$
(c) $\frac{1}{2} d (h_1+h_2)$
(d) $\frac{1}{2} d_1 d_2$
Answer:
Question 2. Match the given dimensions with the area of the figure.
(i) Rhombus, diagonals 10 cm, 16 cm
(ii) Kite, diagonals 12 m, 15 m
(iii) Trapezium, parallel sides 8 cm, 14 cm, height 5 cm
(iv) Quadrilateral, diagonal 20 m, perpendiculars 7 m, 9 m
(a) $60\ \text{cm}^2$
(b) $90\ \text{m}^2$
(c) $80\ \text{cm}^2$
(d) $160\ \text{m}^2$
Answer:
Question 3. Match the method of finding the area of a polygon with its description.
(i) Triangulation
(ii) Using a diagonal and perpendiculars
(iii) Using properties of regular polygons
(iv) Using Heron's formula
(a) Divide into triangles from one vertex
(b) Sum area of triangles formed by a diagonal
(c) Using semi-perimeter and side lengths of triangles
(d) Divide into congruent isosceles triangles meeting at the center
Answer:
Question 4. Match the property related to quadrilateral areas with the figure.
(i) Diagonals are perpendicular
(ii) Opposite sides are parallel
(iii) Exactly one pair of parallel sides
(iv) All sides are equal, diagonals are perpendicular
(a) Trapezium
(b) Parallelogram
(c) Rhombus
(d) Rhombus or Kite
Answer:
Question 5. Match the regular polygon with the number of identical isosceles triangles it can be divided into from the center.
(i) Regular Pentagon
(ii) Regular Hexagon
(iii) Regular Octagon
(iv) Regular Decagon
(a) 10
(b) 5
(c) 8
(d) 6
Answer:
Circles: Circumference and Area
Question 1. Match the term related to circles with its formula (using radius $r$, diameter $d$, circumference $C$, Area $A$).
(i) Circumference
(ii) Area
(iii) Diameter
(iv) Relationship between A and C
(a) $2r$
(b) $2\pi r$
(c) $A = \frac{Cr}{2}$
(d) $\pi r^2$
Answer:
Question 2. Match the given dimension with the calculated circumference (Use $\pi = \frac{22}{7}$).
(i) Radius 7 cm
(ii) Diameter 14 m
(iii) Radius 21 mm
(iv) Diameter 42 cm
(a) 44 m
(b) 132 mm
(c) 44 cm
(d) 132 cm
Answer:
Question 3. Match the given dimension with the calculated area (Use $\pi = \frac{22}{7}$).
(i) Radius 7 cm
(ii) Diameter 14 m
(iii) Radius 21 mm
(iv) Diameter 42 cm
(a) $154\ \text{m}^2$
(b) $1386\ \text{cm}^2$
(c) $154\ \text{cm}^2$
(d) $1386\ \text{mm}^2$
Answer:
Question 4. Match the relationship between radius/diameter and the change in circumference/area.
(i) Radius is doubled
(ii) Diameter is tripled
(iii) Radius is halved
(iv) Diameter is quartered
(a) Circumference is halved
(b) Area becomes nine times
(c) Circumference is doubled
(d) Area becomes one-sixteenth
Answer:
Question 5. Match the concept related to circles with its real-world application.
(i) Circumference
(ii) Area
(iii) Radius
(iv) Ratio of circumference to diameter
(a) Pi ($\pi$)
(b) Space covered by a circular carpet
(c) Distance a wheel travels in one rotation
(d) Distance from the center to the boundary
Answer:
Areas Related to Circles: Sectors and Segments
Question 1. Match the region of a circle with its definition.
(i) Sector
(ii) Segment
(iii) Minor Sector
(iv) Major Segment
(a) Region bounded by an arc and a chord
(b) Region bounded by two radii and an arc
(c) The larger segment formed by a chord
(d) Sector with a central angle less than 180 degrees
Answer:
Question 2. Match the formula with the quantity it calculates (radius $r$, angle $\theta$ in degrees, arc length $l$).
(i) $\frac{\theta}{360} \times 2\pi r$
(ii) $\frac{\theta}{360} \times \pi r^2$
(iii) $2r + l$
(iv) $\frac{1}{2} r l$
(a) Area of a sector
(b) Length of an arc
(c) Perimeter of a sector
(d) Area of a sector (using arc length)
Answer:
Question 3. Match the sector description with its area relative to the total circle area.
(i) Central angle $90^\circ$
(ii) Central angle $180^\circ$
(iii) Central angle $120^\circ$
(iv) Central angle $45^\circ$
(a) $1/8$th of the circle area
(b) $1/4$th of the circle area
(c) $1/2$th of the circle area
(d) $1/3$rd of the circle area
Answer:
Question 4. Match the calculation for finding segment area.
(i) Area of Minor Segment
(ii) Area of Major Segment
(iii) Area of triangle in sector
(iv) Area of corresponding sector
(a) $\frac{1}{2} r^2 \sin \theta$ (for angle $\theta$)
(b) Area of circle - Area of minor segment
(c) $\frac{\theta}{360} \pi r^2$
(d) Area of sector - Area of triangle
Answer:
Question 5. Match the given values (approximate, use $\pi = 3.14$).
(i) Arc length, r=10, $\theta=90^\circ$
(ii) Area of sector, r=10, $\theta=90^\circ$
(iii) Area of triangle in sector, r=10, $\theta=90^\circ$
(iv) Area of minor segment, r=10, $\theta=90^\circ$
(a) 50
(b) 78.5
(c) 15.7
(d) 28.5
Answer:
Area and Perimeter of Combinations of Plane Figures
Question 1. Match the method of calculating area for a composite figure.
(i) Figure formed by non-overlapping shapes
(ii) Figure with a shape removed from within another
(iii) Path around a rectangle (outside)
(iv) Path inside a square (along boundary)
(a) Area of larger outer shape - Area of smaller inner shape
(b) Sum of areas of individual shapes
(c) Area of inner shape - Area of remaining part (Incorrect phrasing)
(d) Area of outer rectangle - Area of inner rectangle
Answer:
Question 2. Match the composite figure with how to calculate its perimeter.
(i) Two squares joined along one side
(ii) Rectangle with a semicircle on one side
(iii) Circular track (ring)
(iv) Square with a square hole in the middle
(a) Sum of outer boundary lengths
(b) Circumference of outer circle + Circumference of inner circle
(c) Sum of 3 sides of rectangle + Arc length of semicircle
(d) Sum of 6 sides of the original squares
Answer:
Question 3. Match the description of a combined figure with a feature of its area calculation.
(i) Path crossing rectangular park
(ii) Circle inscribed in a square
(iii) Square inscribed in a circle
(iv) Semicircles on sides of right triangle
(a) Area of square - Area of circle (Space between)
(b) Overlapping area is subtracted
(c) Related to area of the triangle itself (Lunes of Hippocrates)
(d) Area of circle - Area of square (Space between)
Answer:
Question 4. A square park of side 50 m has a 5 m wide path inside it, along the boundary. Match the dimension/area with its value.
(i) Side of inner square
(ii) Area of outer square
(iii) Area of inner square
(iv) Area of the path
(a) $1600\ \text{m}^2$
(b) $900\ \text{m}^2$
(c) $30\ \text{m}$
(d) $2500\ \text{m}^2$
Answer:
Question 5. Match the combined figure with the type of boundary curves/lines involved in its perimeter.
(i) Square with two semicircles on opposite sides
(ii) Rectangle with four quadrants at corners
(iii) Circle with a square hole
(iv) Two circles touching externally
(a) Two arcs and four straight lines
(b) Two arcs and two straight lines
(c) One arc (circumference)
(d) Two arcs (circumferences)
Answer:
Introduction to Solid Shapes and Basic Terms
Question 1. Match the solid shape property with its description.
(i) Face
(ii) Edge
(iii) Vertex
(iv) Solid
(a) Point where edges meet
(b) Three-dimensional figure
(c) Flat or curved surface
(d) Line segment where faces meet
Answer:
Question 2. Match the solid shape with its type or description.
(i) Cube
(ii) Cylinder
(iii) Pyramid
(iv) Sphere
(a) Round solid
(b) Polyhedron with square faces
(c) Two circular bases and curved surface
(d) Polygonal base and triangular sides meeting at apex
Answer:
Question 3. Match the solid shape with the number of faces it typically has.
(i) Cube
(ii) Square Pyramid
(iii) Triangular Prism
(iv) Sphere
(a) 5
(b) 1
(c) 5
(d) 6
Answer:
Question 4. Match the solid shape with the number of vertices it typically has.
(i) Cuboid
(ii) Cone
(iii) Triangular Prism
(iv) Cylinder
(a) 0
(b) 6
(c) 1
(d) 8
Answer:
Question 5. Match the solid shape with the number of edges it typically has.
(i) Cube
(ii) Square Pyramid
(iii) Cylinder
(iv) Cone
(a) 1
(b) 8
(c) 12
(d) 2
Answer:
Surface Area of Standard Solids
Question 1. Match the surface area type with its definition for a cuboid.
(i) Total Surface Area (TSA)
(ii) Lateral Surface Area (LSA)
(iii) Area of Base
(iv) Area of Top
(a) Area of the bottom face
(b) Sum of the areas of all six faces
(c) Sum of the areas of the four vertical faces
(d) Area of the face opposite to the base
Answer:
Question 2. Match the solid with its Lateral/Curved Surface Area formula (standard notation: $r, h, l, s$).
(i) Cube
(ii) Cuboid
(iii) Cylinder
(iv) Cone
(a) $4s^2$
(b) $\pi r l$
(c) $2\pi r h$
(d) $2(l+w)h$
Answer:
Question 3. Match the solid with its Total Surface Area formula (standard notation: $r, h, l, s, l, w$).
(i) Cube
(ii) Cuboid
(iii) Solid Cylinder
(iv) Solid Cone
(a) $6s^2$
(b) $\pi r (r+l)$
(c) $2(lw+wh+hl)$
(d) $2\pi r (r+h)$
Answer:
Question 4. Match the spherical solid with its surface area formula (radius $r$).
(i) Sphere
(ii) Hemisphere (Curved Surface Area)
(iii) Hemisphere (Total Surface Area)
(iv) Spherical Shell (Outer Surface Area)
(a) $4\pi r^2$
(b) $2\pi r^2$
(c) $3\pi r^2$
(d) $4\pi r^2$ (Assuming $r$ is the outer radius)
Answer:
Question 5. Match the dimension change with the effect on surface area (for a shape like cube or sphere).
(i) Side/Radius doubled
(ii) Side/Radius tripled
(iii) Side/Radius halved
(iv) Side/Radius is $n$ times
(a) Surface area becomes $n^2$ times
(b) Surface area becomes $1/4$ times
(c) Surface area becomes 4 times
(d) Surface area becomes 9 times
Answer:
Volume of Standard Solids
Question 1. Match the solid with its volume formula (standard notation: $s, l, w, h, r$).
(i) Cube
(ii) Cuboid
(iii) Cylinder
(iv) Cone
(a) $\pi r^2 h$
(b) $s^3$
(c) $lwh$
(d) $\frac{1}{3}\pi r^2 h$
Answer:
Question 2. Match the spherical solid with its volume formula (radius $r$).
(i) Sphere
(ii) Hemisphere
(iii) Spherical Shell (Volume of material, outer radius $R$, inner radius $r$)
(iv) Relationship between Sphere V and Hemisphere V
(a) $\frac{2}{3}\pi r^3$
(b) $V_{sphere} = 2 \times V_{hemisphere}$
(c) $\frac{4}{3}\pi r^3$
(d) $\frac{4}{3}\pi (R^3 - r^3)$
Answer:
Question 3. Match the given dimensions with the calculated volume (Use $\pi = \frac{22}{7}$).
(i) Cube, side 10 cm
(ii) Cuboid, 8 cm $\times$ 5 cm $\times$ 4 cm
(iii) Cylinder, radius 7 cm, height 10 cm
(iv) Cone, radius 6 cm, height 7 cm
(a) $160\ \text{cm}^3$
(b) $1540\ \text{cm}^3$
(c) $264\ \text{cm}^3$
(d) $1000\ \text{cm}^3$
Answer:
Question 4. Match the dimension change with the effect on volume (for shapes like cube, sphere, cylinder with fixed base area).
(i) Side/Radius doubled
(ii) Side/Radius tripled
(iii) Side/Radius halved
(iv) Side/Radius is $n$ times
(a) Volume becomes $1/8$ times
(b) Volume becomes 8 times
(c) Volume becomes 27 times
(d) Volume becomes $n^3$ times
Answer:
Question 5. Match the concept related to volume with its application.
(i) Volume of a water tank
(ii) Volume of earth from a well
(iii) Volume of air in a room
(iv) Volume of a solid object
(a) Space occupied by the object
(b) Capacity for liquid
(c) Space for living/working
(d) Material removed from excavation
Answer:
Surface Area and Volume of Combined Solids
Question 1. Match the combined solid with the components of its total surface area (assuming standard joining).
(i) Cone on a Hemisphere
(ii) Cylinder with Hemispherical ends
(iii) Cylinder with Cone removed from top
(iv) Cube with Hemisphere on top
(a) CSA of cylinder + CSA of two hemispheres
(b) 5 faces of cube + CSA of hemisphere + (Area of cube top - Area of hemisphere base)
(c) CSA of cone + CSA of hemisphere
(d) CSA of cylinder + Area of cylinder base + CSA of cone
Answer:
Question 2. Match the combined solid with how to calculate its total volume.
(i) Cone on a Hemisphere
(ii) Cylinder with Hemispherical ends
(iii) Sphere removed from Cylinder
(iv) Cylinder and Cone on same base
(a) Volume of Cylinder + Volume of Cone
(b) Volume of Cylinder - Volume of Sphere
(c) Volume of Cone + Volume of Hemisphere
(d) Volume of Cylinder + 2 $\times$ Volume of Hemisphere
Answer:
Question 3. Match the combined solid description with a specific feature of its calculation.
(i) Toy: cone on hemisphere (same radius)
(ii) Capsule: cylinder with hemispherical ends (same radius)
(iii) Bird-bath: cylinder with hemispherical depression (same radius)
(iv) Pencil: cylinder with conical tip
(a) Volume is Volume of Cylinder - Volume of Hemisphere
(b) Total Surface Area is CSA of Cylinder + CSA of 2 Hemispheres
(c) Total Volume is Volume of Cylinder + Volume of Cone
(d) Joint surface area (circle) is excluded from TSA sum
Answer:
Question 4. Match the given dimensions of a combined solid with an intermediate calculation or resulting dimension.
(i) Toy: Cone on Hemisphere, diameter 7 cm, cone height 10 cm
(ii) Capsule: length 14 mm, diameter 5 mm
(iii) Solid: Cylinder (H=19, D=7) with hemispherical ends
(iv) Wooden article: Cylinder (H=10, R=3.5) with hemispheres scooped out
(a) Radius of hemisphere = 2.5 mm
(b) Radius of hemisphere = 3.5 cm
(c) Height of cylinder = 9 mm
(d) Height of cylinder = 12 cm
Answer:
Question 5. Match the total volume calculation components for combined solids.
(i) Volume of Cylinder + Volume of Hemisphere
(ii) Volume of Cylinder - Volume of Hemisphere
(iii) Volume of Cube + Volume of Cone
(iv) Volume of Cylinder + 2 $\times$ Volume of Hemisphere
(a) Solid with hemispherical depression at one end of cylinder
(b) Solid with hemispherical ends on a cylinder
(c) Solid cube with cone on top
(d) Solid cone on a hemisphere
Answer:
Conversion of Solids and Frustum of a Cone
Question 1. Match the conversion scenario with the property that remains constant.
(i) Melting and recasting a solid
(ii) Digging earth from a well and spreading it
(iii) Drawing a wire from a solid cylinder
(iv) Reshaping clay into a different form
(a) Volume of material
(b) Volume of excavated material = Volume of spread material
(c) Volume of original shape = Volume of new shape
(d) Volume remains constant
Answer:
Question 2. Match the formula with the part of a frustum of a cone (radii $r_1, r_2$, height $h$, slant height $l$).
(i) Volume
(ii) Curved Surface Area
(iii) Area of Top Base
(iv) Slant Height
(a) $\pi r_2^2$ (assuming $r_2$ is top radius)
(b) $\pi (r_1+r_2)l$
(c) $\sqrt{h^2 + (r_1-r_2)^2}$
(d) $\frac{1}{3}\pi h (r_1^2 + r_2^2 + r_1 r_2)$
Answer:
Question 3. A bucket is in the shape of a frustum with radii 14 cm and 7 cm, and height 24 cm. Match the calculation step with the value.
(i) Difference in radii ($r_1-r_2$)
(ii) Square of difference in radii
(iii) Square of height
(iv) Slant height
(a) 576
(b) 49
(c) 7
(d) 25
Answer:
Question 4. A cone is cut by a plane parallel to the base. Match the resulting part with its description.
(i) Upper part
(ii) Lower part
(iii) Sectional plane
(iv) Base of the original cone
(a) A circle parallel to the original base
(b) A smaller cone
(c) A frustum
(d) A circular base
Answer:
Question 5. A solid sphere of radius 3 cm is melted and recast. Match the recasting scenario with the calculation to find the dimension of the new shape.
(i) Recast into a cylinder of height 9 cm
(ii) Recast into 27 smaller spheres
(iii) Recast into a cone with radius 4 cm
(iv) Recast into a hemisphere
(a) $\frac{4}{3}\pi 3^3 = 27 \times \frac{4}{3}\pi r_{new}^3 \implies r_{new} = 1\ \text{cm}$
(b) $\frac{4}{3}\pi 3^3 = \pi r_{cylinder}^2 \times 9 \implies r_{cylinder} = 2\ \text{cm}$
(c) $\frac{4}{3}\pi 3^3 = \frac{2}{3}\pi r_{hemi}^3 \implies r_{hemi} = 3\sqrt[3]{2}\ \text{cm}$
(d) $\frac{4}{3}\pi 3^3 = \frac{1}{3}\pi 4^2 h_{cone} \implies h_{cone} = 6.75\ \text{cm}$
Answer: