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Chapter 14 Oscillations
Introduction
Motion can be categorized in many ways. We have studied non-repetitive motions like rectilinear motion and projectile motion. We have also studied repetitive, or periodic motion, such as uniform circular motion. This chapter focuses on a specific type of periodic motion known as oscillatory motion, where an object moves to and fro about a mean position. Examples include a child on a swing, the pendulum of a clock, and a boat bobbing on water.
The study of oscillations is fundamental to physics as it helps in understanding many phenomena. Vibrating strings in musical instruments, diaphragms in speakers, and the vibrations of atoms in a solid are all examples of oscillatory motion. These phenomena are described using fundamental concepts like period, frequency, displacement, amplitude, and phase, which will be developed in this chapter.
Periodic and Oscillatory Motions
A motion that repeats itself at regular intervals of time is called periodic motion. If a body in periodic motion moves back and forth about a stable equilibrium position, the motion is called oscillatory or vibratory. All oscillatory motions are periodic, but not all periodic motions are oscillatory (e.g., uniform circular motion).
An oscillatory motion is typically caused by a restoring force. When a body is displaced from its equilibrium position, a net force acts on it, trying to bring it back to that equilibrium point. This force gives rise to the oscillations.
The simplest and most important type of oscillatory motion is simple harmonic motion (SHM), which occurs when the restoring force is directly proportional to the displacement from the mean position and is always directed towards it.
Period, Frequency, and Displacement
Period (T) and Frequency ($\nu$)
- The period (T) is the smallest interval of time after which the motion repeats itself. Its SI unit is the second (s).
- The frequency ($\nu$) is the number of repetitions (or cycles) per unit time. It is the reciprocal of the period.
$\nu = \frac{1}{T}$
The SI unit of frequency is s⁻¹, which is named the hertz (Hz). 1 Hz = 1 cycle per second.
Example 1. On an average, a human heart is found to beat 75 times in a minute. Calculate its frequency and period.
Answer:
The beat frequency of the heart is:
$\nu = \frac{75 \text{ beats}}{1 \text{ minute}} = \frac{75 \text{ beats}}{60 \text{ seconds}} = 1.25 \text{ s}^{-1} = 1.25 \text{ Hz}$.
The time period is the reciprocal of the frequency:
$T = \frac{1}{\nu} = \frac{1}{1.25 \text{ Hz}} = 0.8 \text{ s}$.
Displacement
In the context of oscillations, displacement refers to the change in any physical property of the system as a function of time. While it often means position (e.g., the distance of a block from its equilibrium position), it can also refer to other variables like the angle of a pendulum, the voltage across a capacitor in an AC circuit, or the pressure variation in a sound wave.
The displacement in a periodic motion can be represented by a periodic function of time. The simplest periodic functions are sine and cosine functions, for example:
$f(t) = A \cos(\omega t)$
This function repeats itself when its argument, $\omega t$, changes by $2\pi$. So, the period T is given by $\omega T = 2\pi$, or $T = 2\pi/\omega$. The quantity $\omega$ is called the angular frequency.
Simple Harmonic Motion (SHM)
Simple harmonic motion (SHM) is a special type of periodic motion where the displacement of a particle from its equilibrium (mean) position is a sinusoidal function of time.
The displacement $x(t)$ as a function of time $t$ is given by the equation:
$x(t) = A \cos(\omega t + \phi)$
where the terms are defined as:
- $x(t)$: The displacement from the mean position at time $t$.
- $A$: The amplitude, which is the magnitude of the maximum displacement from the mean position. The motion is confined between $-A$ and $+A$.
- $\omega$: The angular frequency, related to the period $T$ and frequency $\nu$ by $\omega = 2\pi/T = 2\pi\nu$. Its unit is radians per second (rad/s).
- $(\omega t + \phi)$: The phase of the motion at time $t$. It determines the state of the particle (its position and velocity) at that instant.
- $\phi$: The phase constant or initial phase. It is the phase at $t=0$ and determines the initial position of the particle.
Simple Harmonic Motion and Uniform Circular Motion
There is a simple and elegant connection between SHM and uniform circular motion (UCM). The projection of a particle undergoing uniform circular motion onto any diameter of the circle executes simple harmonic motion.
Consider a particle P moving uniformly in a circle of radius $A$ with constant angular speed $\omega$. The circle is called the reference circle, and the particle P is the reference particle.
Let the initial angle of the particle's position vector be $\phi$ at $t=0$. At a time $t$, the angle becomes $(\omega t + \phi)$.
The projection of the particle's position onto the x-axis, let's call it P', has a coordinate $x(t)$ given by:
$x(t) = A \cos(\omega t + \phi)$
This is precisely the equation for SHM. Similarly, the projection onto the y-axis, $y(t) = A \sin(\omega t + \phi)$, also represents an SHM.
This connection provides a powerful geometrical tool to visualize and derive the properties of SHM.
Velocity and Acceleration in Simple Harmonic Motion
We can find the velocity and acceleration of a particle in SHM either by taking the projection of the velocity and acceleration of the reference particle in UCM, or by differentiating the displacement equation $x(t) = A \cos(\omega t + \phi)$ with respect to time.
Velocity in SHM
Differentiating the displacement $x(t)$ gives the velocity $v(t)$:
$v(t) = \frac{dx}{dt} = \frac{d}{dt}[A \cos(\omega t + \phi)]$
$v(t) = -A\omega \sin(\omega t + \phi)$
Key features of velocity in SHM:
- The velocity is also a sinusoidal function of time, but it is out of phase with the displacement by $\pi/2$ radians (a quarter cycle).
- The maximum speed, or velocity amplitude, is $v_{max} = A\omega$. This occurs when the particle passes through the mean position ($x=0$).
- The speed is zero at the extreme positions ($x = \pm A$).
The velocity can also be expressed as a function of position $x$:
$v(t) = \pm \omega \sqrt{A^2 - x(t)^2}$
Acceleration in SHM
Differentiating the velocity $v(t)$ gives the acceleration $a(t)$:
$a(t) = \frac{dv}{dt} = \frac{d}{dt}[-A\omega \sin(\omega t + \phi)]$
$a(t) = -A\omega^2 \cos(\omega t + \phi)$
Since $x(t) = A \cos(\omega t + \phi)$, we can write this as:
$a(t) = -\omega^2 x(t)$
Key features of acceleration in SHM:
- The acceleration is directly proportional to the displacement.
- The negative sign indicates that the acceleration is always directed opposite to the displacement, i.e., always towards the mean position.
- The acceleration is maximum in magnitude, $a_{max} = A\omega^2$, at the extreme positions ($x = \pm A$).
- The acceleration is zero at the mean position ($x=0$).
Force Law for Simple Harmonic Motion
According to Newton's second law, $F = ma$. Substituting the expression for acceleration in SHM, $a = -\omega^2 x$, we find the force law for SHM.
$F(t) = m a(t) = m(-\omega^2 x(t))$
$F(t) = -k x(t)$
where $k = m\omega^2$ is a positive constant called the force constant or spring constant.
This provides an alternative and equivalent definition of SHM: Simple harmonic motion is the motion executed by a particle subject to a force that is directly proportional to its displacement from the mean position and is always directed towards the mean position. This type of force is a linear restoring force.
From this force law, we can express the angular frequency and the period of SHM in terms of the system's physical properties (mass $m$ and force constant $k$):
$\omega = \sqrt{\frac{k}{m}} \quad \text{and} \quad T = 2\pi\sqrt{\frac{m}{k}}$
Energy in Simple Harmonic Motion
For a particle executing SHM under the restoring force $F = -kx$, both kinetic and potential energy vary with time and position, but the total mechanical energy remains constant.
Potential Energy (U)
The force $F = -kx$ is a conservative spring-like force. The elastic potential energy stored in the system is:
$U = \frac{1}{2}kx^2 = \frac{1}{2}kA^2 \cos^2(\omega t + \phi)$
Potential energy is zero at the mean position ($x=0$) and maximum at the extreme positions ($x=\pm A$).
Kinetic Energy (K)
The kinetic energy of the oscillating particle is:
$K = \frac{1}{2}mv^2 = \frac{1}{2}m\omega^2 A^2 \sin^2(\omega t + \phi)$
Using $k=m\omega^2$, we can also write this as:
$K = \frac{1}{2}kA^2 \sin^2(\omega t + \phi)$
Kinetic energy is maximum at the mean position ($x=0$) and zero at the extreme positions ($x=\pm A$).
Total Mechanical Energy (E)
The total energy is the sum of the kinetic and potential energies:
$E = K + U = \frac{1}{2}kA^2 \sin^2(\omega t + \phi) + \frac{1}{2}kA^2 \cos^2(\omega t + \phi)$
Using the identity $\sin^2\theta + \cos^2\theta = 1$:
$E = \frac{1}{2}kA^2 = \text{Constant}$
The total mechanical energy in SHM is constant and is proportional to the square of the amplitude. During the oscillation, energy is continuously transformed between potential and kinetic forms.
Some Systems Executing Simple Harmonic Motion
1. Oscillations of a Spring-Mass System
A block of mass $m$ attached to a massless spring with spring constant $k$, oscillating on a frictionless horizontal surface, is a classic example of a simple harmonic oscillator. The restoring force is given by Hooke's Law, $F = -kx$.
This perfectly matches the force law for SHM. Therefore, the motion is SHM with an angular frequency and period given by:
$\omega = \sqrt{\frac{k}{m}} \quad \text{and} \quad T = 2\pi\sqrt{\frac{m}{k}}$
2. The Simple Pendulum
A simple pendulum consists of a point mass (the bob) of mass $m$ suspended from a rigid support by a massless, inextensible string of length $L$.
When the bob is displaced by an angle $\theta$ from the vertical, the force of gravity ($mg$) has a component perpendicular to the string, which acts as the restoring force:
$F_{restoring} = -mg \sin\theta$
This force is not directly proportional to the displacement (which is the arc length $s=L\theta$). Therefore, the motion of a simple pendulum is generally not SHM.
Small Angle Approximation
However, if the angle $\theta$ is small (typically less than about 10 degrees), we can use the approximation $\sin\theta \approx \theta$ (where $\theta$ is in radians). The restoring force then becomes:
$F \approx -mg\theta = -mg\left(\frac{s}{L}\right) = -\left(\frac{mg}{L}\right)s$
Now, the force is proportional to the displacement $s$. This is the condition for SHM. The effective force constant is $k = mg/L$.
The period of a simple pendulum for small oscillations is:
$T = 2\pi\sqrt{\frac{m}{k}} = 2\pi\sqrt{\frac{m}{mg/L}} = 2\pi\sqrt{\frac{L}{g}}$
Notably, for small amplitudes, the period of a simple pendulum is independent of its mass and amplitude.
Damped Simple Harmonic Motion
In real-world systems, oscillations do not continue forever. Frictional or drag forces, collectively known as damping forces, are always present. These forces oppose the motion and cause the mechanical energy of the system to be dissipated, usually as heat. As a result, the amplitude of the oscillations gradually decreases to zero.
The damping force is often proportional to the velocity of the oscillator and acts in the opposite direction:
$F_d = -bv$
where $b$ is the damping constant.
The total force on the oscillator is the sum of the restoring force and the damping force: $F = -kx - bv$. The equation of motion becomes a second-order differential equation:
$m\frac{d^2x}{dt^2} + b\frac{dx}{dt} + kx = 0$
For small damping, the solution to this equation shows that the motion is still oscillatory, but the amplitude decreases exponentially with time:
$x(t) = A_0 e^{-bt/2m} \cos(\omega' t + \phi)$
where $A_0$ is the initial amplitude. The amplitude at any time $t$ is $A(t) = A_0 e^{-bt/2m}$. The angular frequency $\omega'$ is slightly less than the natural angular frequency $\omega = \sqrt{k/m}$.
Forced Oscillations and Resonance
When a damped oscillator is subjected to an external periodic driving force, it undergoes forced oscillations. The oscillator eventually stops oscillating at its own natural frequency and is forced to oscillate at the frequency of the external driver, called the driving frequency ($\omega_d$).
The amplitude of these forced oscillations depends on the driving frequency and the amount of damping. The amplitude is given by:
$A = \frac{F_0/m}{\sqrt{(\omega^2 - \omega_d^2)^2 + (b\omega_d/m)^2}}$
where $F_0$ is the amplitude of the driving force and $\omega$ is the natural frequency of the oscillator.
Resonance
The amplitude of the forced oscillations becomes very large when the driving frequency $\omega_d$ is close to the natural frequency $\omega$ of the oscillator. This phenomenon is called resonance.
At resonance ($\omega_d \approx \omega$), the system absorbs the maximum amount of energy from the driving force, leading to a large amplitude of oscillation. The height and sharpness of the resonance peak depend on the amount of damping. Less damping leads to a higher and sharper peak.
Resonance is a very important phenomenon with numerous applications (e.g., tuning a radio, microwave ovens) and potential dangers (e.g., the collapse of bridges due to marching soldiers or wind, earthquake damage to buildings).
Exercises
Question 14.1. Which of the following examples represent periodic motion?
(a) A swimmer completing one (return) trip from one bank of a river to the other and back.
(b) A freely suspended bar magnet displaced from its N-S direction and released.
(c) A hydrogen molecule rotating about its centre of mass.
(d) An arrow released from a bow.
Answer:
Question 14.2. Which of the following examples represent (nearly) simple harmonic motion and which represent periodic but not simple harmonic motion?
(a) the rotation of earth about its axis.
(b) motion of an oscillating mercury column in a U-tube.
(c) motion of a ball bearing inside a smooth curved bowl, when released from a point slightly above the lower most point.
(d) general vibrations of a polyatomic molecule about its equilibrium position.
Answer:
Question 14.3. Fig. 14.23 depicts four x-t plots for linear motion of a particle. Which of the plots represent periodic motion? What is the period of motion (in case of periodic motion) ?
Answer:
Question 14.4. Which of the following functions of time represent (a) simple harmonic, (b) periodic but not simple harmonic, and (c) non-periodic motion? Give period for each case of periodic motion ($\omega$ is any positive constant):
(a) $\sin(\omega t) – \cos(\omega t)$
(b) $\sin^3(\omega t)$
(c) $3 \cos(\pi/4 – 2\omega t)$
(d) $\cos(\omega t) + \cos(3\omega t) + \cos(5\omega t)$
(e) $\exp(–\omega^2 t^2)$
(f) $1 + \omega t + \omega^2 t^2$
Answer:
Question 14.5. A particle is in linear simple harmonic motion between two points, A and B, 10 cm apart. Take the direction from A to B as the positive direction and give the signs of velocity, acceleration and force on the particle when it is
(a) at the end A,
(b) at the end B,
(c) at the mid-point of AB going towards A,
(d) at 2 cm away from B going towards A,
(e) at 3 cm away from A going towards B, and
(f) at 4 cm away from B going towards A.
Answer:
Question 14.6. Which of the following relationships between the acceleration $a$ and the displacement $x$ of a particle involve simple harmonic motion?
(a) $a = 0.7x$
(b) $a = –200x^2$
(c) $a = –10x$
(d) $a = 100x^3$
Answer:
Question 14.7. The motion of a particle executing simple harmonic motion is described by the displacement function,
$x(t) = A \cos(\omega t + \phi)$.
If the initial (t = 0) position of the particle is 1 cm and its initial velocity is $\omega$ cm/s, what are its amplitude and initial phase angle ? The angular frequency of the particle is $\pi$ s$^{–1}$. If instead of the cosine function, we choose the sine function to describe the SHM : $x = B \sin(\omega t + \alpha)$, what are the amplitude and initial phase of the particle with the above initial conditions.
Answer:
Question 14.8. A spring balance has a scale that reads from 0 to 50 kg. The length of the scale is 20 cm. A body suspended from this balance, when displaced and released, oscillates with a period of 0.6 s. What is the weight of the body ?
Answer:
Question 14.9. A spring having with a spring constant 1200 N m$^{–1}$ is mounted on a horizontal table as shown in Fig. 14.24. A mass of 3 kg is attached to the free end of the spring. The mass is then pulled sideways to a distance of 2.0 cm and released.
Determine (i) the frequency of oscillations, (ii) maximum acceleration of the mass, and (iii) the maximum speed of the mass.
Answer:
Question 14.10. In Exercise 14.9, let us take the position of mass when the spring is unstreched as x = 0, and the direction from left to right as the positive direction of x-axis. Give x as a function of time t for the oscillating mass if at the moment we start the stopwatch (t = 0), the mass is
(a) at the mean position,
(b) at the maximum stretched position, and
(c) at the maximum compressed position.
In what way do these functions for SHM differ from each other, in frequency, in amplitude or the initial phase?
Answer:
Question 14.11. Figures 14.25 correspond to two circular motions. The radius of the circle, the period of revolution, the initial position, and the sense of revolution (i.e. clockwise or anti-clockwise) are indicated on each figure.
Obtain the corresponding simple harmonic motions of the x-projection of the radius vector of the revolving particle P, in each case.
Answer:
Question 14.12. Plot the corresponding reference circle for each of the following simple harmonic motions. Indicate the initial (t =0) position of the particle, the radius of the circle, and the angular speed of the rotating particle. For simplicity, the sense of rotation may be fixed to be anticlockwise in every case: (x is in cm and t is in s).
(a) $x = –2 \sin(3t + \pi/3)$
(b) $x = \cos(\pi/6 – t)$
(c) $x = 3 \sin(2\pi t + \pi/4)$
(d) $x = 2 \cos(\pi t)$
Answer:
Question 14.13. Figure 14.26 (a) shows a spring of force constant k clamped rigidly at one end and a mass m attached to its free end. A force F applied at the free end stretches the spring. Figure 14.26 (b) shows the same spring with both ends free and attached to a mass m at either end. Each end of the spring in Fig. 14.26(b) is stretched by the same force F.
(a) What is the maximum extension of the spring in the two cases ?
(b) If the mass in Fig. (a) and the two masses in Fig. (b) are released, what is the period of oscillation in each case ?
Answer:
Question 14.14. The piston in the cylinder head of a locomotive has a stroke (twice the amplitude) of 1.0 m. If the piston moves with simple harmonic motion with an angular frequency of 200 rad/min, what is its maximum speed ?
Answer:
Question 14.15. The acceleration due to gravity on the surface of moon is 1.7 m s$^{–2}$. What is the time period of a simple pendulum on the surface of moon if its time period on the surface of earth is 3.5 s ? (g on the surface of earth is 9.8 m s$^{–2}$)
Answer:
Question 14.16. Answer the following questions :
(a) Time period of a particle in SHM depends on the force constant k and mass m of the particle: $T = 2\pi\sqrt{\frac{m}{k}}$. A simple pendulum executes SHM approximately. Why then is the time period of a pendulum independent of the mass of the pendulum?
(b) The motion of a simple pendulum is approximately simple harmonic for small angle oscillations. For larger angles of oscillation, a more involved analysis shows that T is greater than $2\pi\sqrt{\frac{l}{g}}$. Think of a qualitative argument to appreciate this result.
(c) A man with a wristwatch on his hand falls from the top of a tower. Does the watch give correct time during the free fall ?
(d) What is the frequency of oscillation of a simple pendulum mounted in a cabin that is freely falling under gravity ?
Answer:
Question 14.17. A simple pendulum of length l and having a bob of mass M is suspended in a car. The car is moving on a circular track of radius R with a uniform speed v. If the pendulum makes small oscillations in a radial direction about its equilibrium position, what will be its time period ?
Answer:
Question 14.18. A cylindrical piece of cork of density of base area A and height h floats in a liquid of density $\rho_l$. The cork is depressed slightly and then released. Show that the cork oscillates up and down simple harmonically with a period
$T = 2\pi\sqrt{\frac{h\rho}{\rho_l g}}$
where $\rho$ is the density of cork. (Ignore damping due to viscosity of the liquid).
Answer:
Question 14.19. One end of a U-tube containing mercury is connected to a suction pump and the other end to atmosphere. A small pressure difference is maintained between the two columns. Show that, when the suction pump is removed, the column of mercury in the U-tube executes simple harmonic motion.
Answer:
Additional Exercises
Question 14.20. An air chamber of volume V has a neck area of cross section a into which a ball of mass m just fits and can move up and down without any friction (Fig.14.27). Show that when the ball is pressed down a little and released , it executes SHM. Obtain an expression for the time period of oscillations assuming pressure-volume variations of air to be isothermal [see Fig. 14.27].
Answer:
Question 14.21. You are riding in an automobile of mass 3000 kg. Assuming that you are examining the oscillation characteristics of its suspension system. The suspension sags 15 cm when the entire automobile is placed on it. Also, the amplitude of oscillation decreases by 50% during one complete oscillation. Estimate the values of (a) the spring constant k and (b) the damping constant b for the spring and shock absorber system of one wheel, assuming that each wheel supports 750 kg.
Answer:
Question 14.22. Show that for a particle in linear SHM the average kinetic energy over a period of oscillation equals the average potential energy over the same period.
Answer:
Question 14.23. A circular disc of mass 10 kg is suspended by a wire attached to its centre. The wire is twisted by rotating the disc and released. The period of torsional oscillations is found to be 1.5 s. The radius of the disc is 15 cm. Determine the torsional spring constant of the wire. (Torsional spring constant $\alpha$ is defined by the relation $J = –\alpha \theta$, where J is the restoring couple and $\theta$ the angle of twist).
Answer:
Question 14.24. A body describes simple harmonic motion with an amplitude of 5 cm and a period of 0.2 s. Find the acceleration and velocity of the body when the displacement is
(a) 5 cm
(b) 3 cm
(c) 0 cm.
Answer:
Question 14.25. A mass attached to a spring is free to oscillate, with angular velocity $\omega$, in a horizontal plane without friction or damping. It is pulled to a distance $x_0$ and pushed towards the centre with a velocity $v_0$ at time t = 0. Determine the amplitude of the resulting oscillations in terms of the parameters $\omega, x_0$ and $v_0$. [Hint : Start with the equation $x = a \cos(\omega t+\theta)$ and note that the initial velocity is negative.]
Answer:
 
