Molecular Mass And Mole Concept
Molecular Mass And Mole Concept
Molecular Mass
Definition: Molecular mass is the sum of the atomic masses of all the atoms present in a single molecule of a substance. It is a dimensionless quantity, often expressed in atomic mass units (amu). In practice, it is numerically equivalent to the molar mass expressed in grams per mole (g/mol).
Calculation: To determine the molecular mass of a compound, you need to know the chemical formula and the atomic masses of each element present in the compound. These atomic masses are typically found on the periodic table. The atomic mass of an element is essentially the average mass of its naturally occurring isotopes, expressed in amu.
Derivation/Understanding:
Consider a molecule of methane ($CH_4$). Its chemical formula tells us it contains one carbon atom and four hydrogen atoms.
From the periodic table:
- Atomic mass of Carbon (C) $\approx$ 12.011 amu
- Atomic mass of Hydrogen (H) $\approx$ 1.008 amu
To find the molecular mass of $CH_4$, we sum the atomic masses of all constituent atoms:
Molecular mass of $CH_4$ = (1 $\times$ Atomic mass of C) + (4 $\times$ Atomic mass of H)
Molecular mass of $CH_4$ = (1 $\times$ 12.011 amu) + (4 $\times$ 1.008 amu)
Molecular mass of $CH_4$ = 12.011 amu + 4.032 amu
Molecular mass of $CH_4$ = 16.043 amu
Why amu? The atomic mass unit (amu) is a standard unit of mass used to express the mass of atoms and molecules. It is defined as 1/12th the mass of an atom of carbon-12. This unit is convenient because atomic and molecular masses are very small.
Formula Unit Mass
Definition: Formula unit mass applies specifically to ionic compounds. Ionic compounds do not exist as discrete molecules but rather as a crystal lattice structure where ions are arranged in a repeating three-dimensional pattern. The formula unit represents the simplest whole-number ratio of ions in the compound. Formula unit mass is the sum of the atomic masses of all the atoms in one formula unit of an ionic compound, also expressed in atomic mass units (amu).
Calculation: Similar to molecular mass, we sum the atomic masses of the constituent elements based on their empirical formula.
Derivation/Understanding:
Consider the ionic compound sodium chloride (NaCl). Its formula unit represents one sodium ion ($Na^+$) and one chloride ion ($Cl^-$).
From the periodic table:
- Atomic mass of Sodium (Na) $\approx$ 22.990 amu
- Atomic mass of Chlorine (Cl) $\approx$ 35.453 amu
To find the formula unit mass of NaCl:
Formula unit mass of NaCl = (1 $\times$ Atomic mass of Na) + (1 $\times$ Atomic mass of Cl)
Formula unit mass of NaCl = (1 $\times$ 22.990 amu) + (1 $\times$ 35.453 amu)
Formula unit mass of NaCl = 22.990 amu + 35.453 amu
Formula unit mass of NaCl = 58.443 amu
Distinction between Molecular Mass and Formula Unit Mass:
The term "molecular mass" is used for substances that exist as discrete molecules (e.g., $H_2O$, $CO_2$, $O_2$), while "formula unit mass" is used for ionic compounds (e.g., NaCl, $MgCl_2$, $KNO_3$) which form crystal lattices.
Mole Concept
Definition: The mole is a fundamental unit in chemistry that represents a specific, very large number of entities (atoms, molecules, ions, etc.). It is defined as the amount of substance that contains exactly $6.02214076 \times 10^{23}$ elementary entities. This number is known as Avogadro's constant or Avogadro's number ($N_A$).
Origin of Avogadro's Number: Avogadro's number is derived from the definition of the mole, which is based on the carbon-12 isotope. One mole of carbon-12 atoms has a mass of exactly 12 grams, and it contains $6.02214076 \times 10^{23}$ atoms.
Significance: The mole concept is crucial because it allows chemists to relate the mass of a substance (which we can measure in the lab) to the number of particles (which are too small to count directly). It provides a universal way to quantify matter.
Analogy: Think of a "dozen" eggs. A dozen always means 12 eggs, regardless of the size or weight of individual eggs. Similarly, a mole always means $6.022 \times 10^{23}$ of whatever entity you are referring to (atoms, molecules, etc.).
Key Relationships:
- 1 mole of atoms = $6.022 \times 10^{23}$ atoms
- 1 mole of molecules = $6.022 \times 10^{23}$ molecules
- 1 mole of ions = $6.022 \times 10^{23}$ ions
Molar Mass: This is the mass of one mole of a substance, expressed in grams per mole (g/mol). It is numerically equal to the atomic mass, molecular mass, or formula unit mass expressed in amu.
- Molar Mass of an Element: If an element's atomic mass is $X$ amu, its molar mass is $X$ g/mol.
- Molar Mass of a Molecule: If a molecule's molecular mass is $Y$ amu, its molar mass is $Y$ g/mol.
- Molar Mass of an Ionic Compound: If an ionic compound's formula unit mass is $Z$ amu, its molar mass is $Z$ g/mol.
Connecting Mass, Moles, and Particles:
The following formulas are essential:
- To find the number of moles from mass: $n = \frac{\text{mass of substance (g)}}{\text{Molar mass of substance (g/mol)}}$
- To find the mass from the number of moles: $\text{mass of substance (g)} = n \times \text{Molar mass of substance (g/mol)}$
- To find the number of particles from moles: $N = n \times N_A$
- To find the number of particles from mass: $N = \frac{\text{mass of substance (g)}}{\text{Molar mass of substance (g/mol)}} \times N_A$
Derivation: Molar mass is the mass of 1 mole. If we have a total mass 'm' and each mole weighs 'M', then the number of moles 'n' is simply 'm' divided by 'M'. $m = n \times M \Rightarrow n = m/M$
Derivation: If 1 mole contains $N_A$ particles, then 'n' moles will contain $n \times N_A$ particles.
Atomic And Molecular Masses
Atomic Mass
Definition: Atomic mass is the mass of an atom of a chemical element. Historically, it was compared to hydrogen, then oxygen. Today, it is defined in relation to carbon-12.
Atomic Mass Unit (amu): The atomic mass unit (amu), also known as the dalton (Da), is a unit of mass used to express the mass of atoms and molecules. It is defined as one-twelfth (1/12) of the mass of an unbound neutral atom of carbon-12 ($^{12}C$) in its ground state.
$1 \text{ amu} = \frac{1}{12} \times \text{mass of one atom of } ^{12}C$
The value of 1 amu is approximately $1.66053906660 \times 10^{-24}$ grams.
Notation: Atomic mass is often represented by the symbol 'u' (unified atomic mass unit), which is now preferred over amu.
Average Atomic Mass
Definition: Most elements exist naturally as a mixture of isotopes. Isotopes are atoms of the same element that have the same number of protons but different numbers of neutrons, and therefore different masses. The average atomic mass is the weighted average of the masses of all naturally occurring isotopes of an element.
Calculation:
Average Atomic Mass = $\sum_{i=1}^{n} (\text{Mass of Isotope}_i \times \text{Relative Abundance of Isotope}_i)$
Where:
- $n$ is the number of isotopes of the element.
- Mass of Isotope$_i$ is the mass of the $i$-th isotope (usually expressed in amu).
- Relative Abundance of Isotope$_i$ is the fractional abundance of the $i$-th isotope (expressed as a decimal, where the sum of all abundances is 1).
Example: Chlorine exists as two main isotopes, Chlorine-35 ($^{35}Cl$) and Chlorine-37 ($^{37}Cl$).
- Mass of $^{35}Cl \approx 34.96885$ amu
- Mass of $^{37}Cl \approx 36.96590$ amu
- Natural abundance of $^{35}Cl \approx 75.76\%$ (or 0.7576)
- Natural abundance of $^{37}Cl \approx 24.24\%$ (or 0.2424)
Average Atomic Mass of Cl = $(34.96885 \text{ amu} \times 0.7576) + (36.96590 \text{ amu} \times 0.2424)$
Average Atomic Mass of Cl $\approx 26.4955 + 8.9587$
Average Atomic Mass of Cl $\approx$ 35.454 amu
This is the value you see for chlorine on the periodic table.
Molecular Mass
Definition: The molecular mass of a substance is the sum of the atomic masses of all the atoms in one molecule of that substance. It is expressed in atomic mass units (amu).
Calculation: Sum the atomic masses of each element in the molecule, multiplied by the number of atoms of that element present in the molecule.
Example: Glucose ($C_6H_{12}O_6$)
- Atomic mass of Carbon (C) $\approx$ 12.011 amu
- Atomic mass of Hydrogen (H) $\approx$ 1.008 amu
- Atomic mass of Oxygen (O) $\approx$ 15.999 amu
Molecular mass of $C_6H_{12}O_6$ = (6 $\times$ 12.011 amu) + (12 $\times$ 1.008 amu) + (6 $\times$ 15.999 amu)
Molecular mass of $C_6H_{12}O_6$ = 72.066 amu + 12.096 amu + 95.994 amu
Molecular mass of $C_6H_{12}O_6$ = 180.156 amu
Formula Mass
Definition: Formula mass is the sum of the atomic masses of all the atoms in the empirical formula of an ionic compound. It is used because ionic compounds form crystal lattices, not discrete molecules.
Calculation: Similar to molecular mass, sum the atomic masses of each element in the empirical formula, multiplied by the number of atoms of that element.
Example: Magnesium Chloride ($MgCl_2$)
- Atomic mass of Magnesium (Mg) $\approx$ 24.305 amu
- Atomic mass of Chlorine (Cl) $\approx$ 35.453 amu
Formula mass of $MgCl_2$ = (1 $\times$ 24.305 amu) + (2 $\times$ 35.453 amu)
Formula mass of $MgCl_2$ = 24.305 amu + 70.906 amu
Formula mass of $MgCl_2$ = 95.211 amu
Mole Concept And Molar Masses
The mole concept and molar mass are inextricably linked. The mole provides a way to count entities at the atomic and molecular level, while molar mass provides the conversion factor between the number of moles and the measurable mass of a substance.
Molar Mass
Definition: The molar mass of a substance is the mass of one mole of that substance. The standard unit for molar mass is grams per mole (g/mol).
Relationship to amu: Numerically, the molar mass in g/mol is equal to the atomic mass, molecular mass, or formula unit mass in amu.
- For an element like Helium (He), atomic mass $\approx$ 4.003 amu. Therefore, molar mass of He $\approx$ 4.003 g/mol.
- For a molecule like Carbon Dioxide ($CO_2$), molecular mass $\approx$ 44.010 amu (12.011 + 2 * 15.999). Therefore, molar mass of $CO_2 \approx$ 44.010 g/mol.
- For an ionic compound like Potassium Nitrate ($KNO_3$), formula unit mass $\approx$ 101.103 amu (39.098 + 14.007 + 3 * 15.999). Therefore, molar mass of $KNO_3 \approx$ 101.103 g/mol.
Calculating Molar Mass
To calculate the molar mass of a compound, you follow these steps:
- Determine the chemical formula of the compound.
- Find the atomic mass of each element in the compound from the periodic table.
- Multiply the atomic mass of each element by the number of atoms of that element in the formula.
- Sum these values to get the molecular mass (in amu) or formula unit mass (in amu).
- The molar mass is this value expressed in grams per mole (g/mol).
The Mole (n) and Mass (m) Relationship
The number of moles ($n$) of a substance can be determined from its mass ($m$) and its molar mass ($M$) using the following formula:
$$n = \frac{m}{M}$$Where:
- $n$ = number of moles (unit: mol)
- $m$ = mass of the substance (unit: grams, g)
- $M$ = molar mass of the substance (unit: grams per mole, g/mol)
Derivation:
By definition, molar mass ($M$) is the mass of 1 mole of a substance.
$M \frac{\text{g}}{\text{mol}} = \frac{\text{Mass of 1 mole}}{\text{1 mole}}$
If we have $n$ moles of a substance, its total mass $m$ would be:
$m = n \times M$
Rearranging this equation to solve for the number of moles, we get:
$$n = \frac{m}{M}$$Avogadro's Number ($N_A$) and the Number of Particles (N)
Avogadro's number ($N_A$) is the constant that relates the number of moles to the number of elementary entities (atoms, molecules, ions, etc.).
$N_A \approx 6.022 \times 10^{23}$ entities/mol
The number of particles ($N$) in a given amount of substance can be calculated as:
$$N = n \times N_A$$Derivation:
If 1 mole contains $N_A$ particles, then $n$ moles will contain $n$ times $N_A$ particles.
Combining these relationships, we can directly calculate the number of particles from the mass of a substance:
$$N = \frac{m}{M} \times N_A$$Illustrative Examples:
Example 1: Calculate the mass of 0.5 moles of sodium hydroxide (NaOH).
Example 1. Calculate the mass of 0.5 moles of sodium hydroxide (NaOH).
Answer:
Step 1: Calculate the molar mass of NaOH.
Atomic mass of Na $\approx$ 23.0 g/mol
Atomic mass of O $\approx$ 16.0 g/mol
Atomic mass of H $\approx$ 1.0 g/mol
Molar mass of NaOH ($M$) = 23.0 + 16.0 + 1.0 = 40.0 g/mol
Step 2: Use the formula $m = n \times M$.
Given $n = 0.5$ mol and $M = 40.0$ g/mol.
Mass ($m$) = 0.5 mol $\times$ 40.0 g/mol = 20.0 g
Therefore, the mass of 0.5 moles of NaOH is 20.0 grams.
Example 2: How many moles are there in 90 grams of water ($H_2O$)?
Example 2. How many moles are there in 90 grams of water ($H_2O$)?
Answer:
Step 1: Calculate the molar mass of $H_2O$.
Atomic mass of H $\approx$ 1.0 g/mol
Atomic mass of O $\approx$ 16.0 g/mol
Molar mass of $H_2O$ ($M$) = (2 $\times$ 1.0) + 16.0 = 18.0 g/mol
Step 2: Use the formula $n = \frac{m}{M}$.
Given $m = 90$ g and $M = 18.0$ g/mol.
Number of moles ($n$) = $\frac{90 \text{ g}}{18.0 \text{ g/mol}} = 5.0$ mol
Therefore, there are 5.0 moles in 90 grams of water.
Example 3: Calculate the number of molecules in 44 grams of carbon dioxide ($CO_2$).
Example 3. Calculate the number of molecules in 44 grams of carbon dioxide ($CO_2$).
Answer:
Step 1: Calculate the molar mass of $CO_2$.
Atomic mass of C $\approx$ 12.0 g/mol
Atomic mass of O $\approx$ 16.0 g/mol
Molar mass of $CO_2$ ($M$) = 12.0 + (2 $\times$ 16.0) = 12.0 + 32.0 = 44.0 g/mol
Step 2: Calculate the number of moles ($n$).
Given $m = 44$ g and $M = 44.0$ g/mol.
Number of moles ($n$) = $\frac{44 \text{ g}}{44.0 \text{ g/mol}} = 1.0$ mol
Step 3: Calculate the number of molecules ($N$) using Avogadro's number ($N_A \approx 6.022 \times 10^{23}$ molecules/mol).
Number of molecules ($N$) = $n \times N_A$
Number of molecules ($N$) = 1.0 mol $\times$ $6.022 \times 10^{23}$ molecules/mol = $6.022 \times 10^{23}$ molecules
Therefore, there are $6.022 \times 10^{23}$ molecules in 44 grams of carbon dioxide.
Example 4: How many atoms of oxygen are there in 0.5 moles of sulfuric acid ($H_2SO_4$)?
Example 4. How many atoms of oxygen are there in 0.5 moles of sulfuric acid ($H_2SO_4$)?
Answer:
Step 1: Identify the number of oxygen atoms in one molecule of $H_2SO_4$.
From the formula $H_2SO_4$, there are 4 oxygen atoms per molecule.
Step 2: Calculate the total number of $H_2SO_4$ molecules in 0.5 moles.
Number of molecules ($N$) = Number of moles ($n$) $\times$ Avogadro's Number ($N_A$)
Number of $H_2SO_4$ molecules = 0.5 mol $\times$ $6.022 \times 10^{23}$ molecules/mol = $3.011 \times 10^{23}$ molecules
Step 3: Calculate the total number of oxygen atoms.
Total Oxygen atoms = (Number of $H_2SO_4$ molecules) $\times$ (Oxygen atoms per molecule)
Total Oxygen atoms = ($3.011 \times 10^{23}$ molecules) $\times$ (4 atoms/molecule)
Total Oxygen atoms = $1.2044 \times 10^{24}$ atoms
Therefore, there are $1.2044 \times 10^{24}$ atoms of oxygen in 0.5 moles of sulfuric acid.