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Chapter 1: Chemical Reactions And Equations
In our daily lives, we observe numerous changes around us. Some common examples include:
- Milk souring when left at room temperature in warm weather.
- Iron objects developing a reddish-brown coating when exposed to humid air.
- Grapes transforming into alcohol during fermentation.
- Raw food becoming cooked and palatable.
- Food breaking down within our bodies during digestion.
- Breathing, where our bodies utilise oxygen and produce carbon dioxide.
In all these situations, the original substances undergo fundamental changes, resulting in new substances with different properties. We learned in earlier studies that matter can undergo physical changes (like melting or boiling, where the substance's identity doesn't change) or chemical changes (where a new substance is formed). Whenever a chemical change takes place, we can say that a chemical reaction has occurred.
But how do we know for certain that a chemical reaction has happened? Several observable changes can indicate a chemical reaction.
1.1 Chemical Equations
A chemical reaction can be described in words, but this is often lengthy. A more concise and practical way to represent a chemical reaction is by using a chemical equation.
1.1.1 Writing A Chemical Equation
Let's consider the example of burning magnesium ribbon in air. The word description is: "when a magnesium ribbon is burnt in oxygen, it gets converted to magnesium oxide."
A simpler way to represent this is using a word equation:
Magnesium + Oxygen $\longrightarrow$ Magnesium oxide
In a word equation:
- The substances that react are called reactants. They are written on the Left-Hand Side (LHS) of an arrow.
- The new substance(s) formed are called products. They are written on the Right-Hand Side (RHS) of the arrow.
- A plus sign (+) is used between reactants if there are two or more. Similarly, a plus sign is used between products if there are two or more.
- An arrow ($\longrightarrow$) separates the reactants from the products and points towards the products, indicating the direction of the reaction.
Burning magnesium ribbon produces a dazzling white flame and leaves behind a white powder, which is magnesium oxide ($\text{MgO}$). This is formed by the reaction between magnesium ($\text{Mg}$) and oxygen ($\text{O}_2$) from the air.
Even more concise and useful than word equations are chemical equations written using chemical formulae. Replacing the words with chemical formulae, the word equation for burning magnesium becomes:
$\text{Mg} + \text{O}_2 \longrightarrow \text{MgO}$
This form represents the chemical reaction using symbols and formulae.
1.1.2 Balanced Chemical Equations
A chemical equation written using formulae, like $\text{Mg} + \text{O}_2 \longrightarrow \text{MgO}$, is called a skeletal chemical equation. A skeletal equation is like an outline of the reaction.
We need to check if the number of atoms of each element on the reactant side (LHS) is equal to the number of atoms of the same element on the product side (RHS). Let's count the atoms in the skeletal equation for magnesium burning:
| Element | Number of atoms in reactants ($\text{Mg} + \text{O}_2$) | Number of atoms in products ($\text{MgO}$) |
|---|---|---|
| Magnesium (Mg) | 1 | 1 |
| Oxygen (O) | 2 | 1 |
The number of Mg atoms is equal, but the number of O atoms is not (2 on LHS, 1 on RHS). This skeletal equation is unbalanced. An unbalanced equation does not follow the Law of Conservation of Mass, which states that mass can neither be created nor destroyed in a chemical reaction. This means the total mass of reactants must equal the total mass of products. Since atoms are conserved in chemical reactions (they are only rearranged, not created or destroyed), the total number of atoms of each element must be the same on both sides of a chemical equation.
A chemical equation where the number of atoms of each element is the same on both the reactant and product sides is called a balanced chemical equation. Balancing ensures that the equation accurately reflects the Law of Conservation of Mass.
We balance chemical equations using a process called the hit-and-trial method, which involves adjusting coefficients (numbers placed in front of formulae) to make the number of atoms equal on both sides. We cannot change the chemical formulae themselves (e.g., we can use $2\text{H}_2\text{O}$ but not $\text{H}_4\text{O}_2$ or $\text{H}_2\text{O}_2$ if the substance is water). We aim to use the smallest possible whole number coefficients.
Steps for Balancing Chemical Equations (Using $\text{Fe} + \text{H}_2\text{O} \longrightarrow \text{Fe}_3\text{O}_4 + \text{H}_2$ example):
- Write the skeletal equation and draw boxes around formulae: This reminds us not to change the formulae.
$\text{Fe} + \text{H}_2\text{O} \longrightarrow \text{Fe}_3\text{O}_4 + \text{H}_2$
- List the number of atoms of each element on both sides:
Element Number of atoms on LHS Number of atoms on RHS Fe 1 3 H 2 2 O 1 4 - Start balancing with the element that has the maximum number of atoms in the most complex compound: In $\text{Fe}_3\text{O}_4$, Oxygen has 4 atoms (maximum). On the LHS, $\text{H}_2\text{O}$ has 1 oxygen atom. To balance oxygen, multiply $\text{H}_2\text{O}$ by 4 on the LHS. Place the coefficient *outside* the box.
$\text{Fe} + 4\text{ H}_2\text{O} \longrightarrow \text{Fe}_3\text{O}_4 + \text{H}_2$ (Partly balanced)
- Balance the next element (Hydrogen) affected by the coefficient: The 4 coefficient on $\text{H}_2\text{O}$ gives $4 \times 2 = 8$ hydrogen atoms on the LHS. On the RHS, $\text{H}_2$ has 2 hydrogen atoms. To balance hydrogen, multiply $\text{H}_2$ by 4 on the RHS.
$\text{Fe} + 4\text{ H}_2\text{O} \longrightarrow \text{Fe}_3\text{O}_4 + 4\text{ H}_2$ (Partly balanced)
- Balance the remaining element (Iron): On the RHS, $\text{Fe}_3\text{O}_4$ has 3 iron atoms. On the LHS, Fe has 1 iron atom. To balance iron, multiply Fe by 3 on the LHS.
$3\text{ Fe} + 4\text{ H}_2\text{O} \longrightarrow \text{Fe}_3\text{O}_4 + 4\text{ H}_2$ (Balanced equation)
- Verify the balanced equation by counting atoms on both sides:
Element Number of atoms on LHS ($3\text{Fe} + 4\text{H}_2\text{O}$) Number of atoms on RHS ($\text{Fe}_3\text{O}_4 + 4\text{H}_2$) Fe $3 \times 1 = 3$ 3 H $4 \times 2 = 8$ $4 \times 2 = 8$ O $4 \times 1 = 4$ 4 Since the number of atoms of each element is equal on both sides, the equation is balanced.
- Adding physical states and conditions (Optional but informative): To make the equation more informative, we can indicate the physical states of reactants and products using symbols: (s) for solid, (l) for liquid, (g) for gas, and (aq) for aqueous solution (dissolved in water). Reaction conditions (temperature, pressure, catalyst) can be shown above/below the arrow.
$3\text{Fe(s)} + 4\text{H}_2\text{O(g)} \longrightarrow \text{Fe}_3\text{O}_4\text{(s)} + 4\text{H}_2\text{(g)}$
Here, $\text{H}_2\text{O(g)}$ indicates water in the form of steam reacting with solid iron.
Example conditions: $\text{CO(g)} + 2\text{H}_2\text{(g)} \xrightarrow{340 \text{ atm}} \text{CH}_3\text{OH(l)}$ (formation of methanol under high pressure).
$6\text{CO}_2\text{(aq)} + 12\text{H}_2\text{O(l)} \xrightarrow{\text{Sunlight}}{\text{Chlorophyll}} \text{C}_6\text{H}_{12}\text{O}_6\text{(aq)} + 6\text{O}_2\text{(aq)} + 6\text{H}_2\text{O(l)}$ (photosynthesis)
Indicators of a Chemical Reaction: Based on observations from activities, a chemical reaction has likely occurred if there is:
- A change in state (solid to liquid, gas to solid, etc.).
- A change in colour.
- Evolution (release) of a gas.
- A change in temperature (reaction mixture becomes hotter or colder).
- Formation of a precipitate (an insoluble solid formed from mixing solutions).
1.2 Types Of Chemical Reactions
Chemical reactions involve the breaking of old chemical bonds within reactant molecules and the formation of new chemical bonds to create product molecules. Atoms are simply rearranged, not created or destroyed.
1.2.1 Combination Reaction
In a combination reaction, two or more reactants (elements or compounds) combine to form a single product.
Example: When calcium oxide (quicklime, $\text{CaO}$) reacts with water ($\text{H}_2\text{O}$), it forms calcium hydroxide (slaked lime, $\text{Ca(OH)}_2$). This reaction is vigorous and releases a large amount of heat.
$\text{CaO(s)} + \text{H}_2\text{O(l)} \longrightarrow \text{Ca(OH)}_2\text{(aq)} + \text{Heat}$
Here, two substances ($\text{CaO}$ and $\text{H}_2\text{O}$) combine to form one substance ($\text{Ca(OH)}_2$), fitting the definition of a combination reaction.
This reaction is also an example of an exothermic reaction because heat is released during the process, causing the reaction mixture to become warm.
Other Examples of Combination Reactions:
- Burning of carbon (coal): $\text{C(s)} + \text{O}_2\text{(g)} \longrightarrow \text{CO}_2\text{(g)}$
- Formation of water: $2\text{H}_2\text{(g)} + \text{O}_2\text{(g)} \longrightarrow 2\text{H}_2\text{O(l)}$
Exothermic Reactions: Reactions that release energy (usually as heat). Examples include:
- Burning of natural gas (methane): $\text{CH}_4\text{(g)} + 2\text{O}_2\text{(g)} \longrightarrow \text{CO}_2\text{(g)} + 2\text{H}_2\text{O(g)} + \text{Heat}$
- Respiration: The process in living cells where glucose combines with oxygen to produce carbon dioxide, water, and energy. $\text{C}_6\text{H}_{12}\text{O}_6\text{(aq)} + 6\text{O}_2\text{(aq)} \longrightarrow 6\text{CO}_2\text{(aq)} + 6\text{H}_2\text{O(l)} + \text{energy}$
- Decomposition of vegetable matter into compost.
Calcium hydroxide solution (slaked lime) is used for whitewashing walls. It slowly reacts with carbon dioxide in the air to form a thin, shiny layer of calcium carbonate ($\text{CaCO}_3$) after two to three days. $\text{Ca(OH)}_2\text{(aq)} + \text{CO}_2\text{(g)} \longrightarrow \text{CaCO}_3\text{(s)} + \text{H}_2\text{O(l)}$
1.2.2 Decomposition Reaction
A decomposition reaction is the opposite of a combination reaction. In a decomposition reaction, a single reactant breaks down to give two or more simpler products.
Decomposition reactions typically require energy input to break the bonds in the reactant. This energy can be supplied in the form of heat, light, or electricity.
- Thermal Decomposition: Decomposition caused by heating.
Example 1: Heating ferrous sulphate crystals ($\text{FeSO}_4 \cdot 7\text{H}_2\text{O}$, green colour). When heated, they first lose water and the colour changes. Then, they decompose into ferric oxide ($\text{Fe}_2\text{O}_3$, brown/black solid), sulphur dioxide ($\text{SO}_2$, gas with characteristic burning sulphur smell), and sulphur trioxide ($\text{SO}_3$, gas).
$2\text{FeSO}_4\text{(s)} \xrightarrow{\text{Heat}} \text{Fe}_2\text{O}_3\text{(s)} + \text{SO}_2\text{(g)} + \text{SO}_3\text{(g)}$
Example 2: Heating calcium carbonate ($\text{CaCO}_3$, limestone). It decomposes into calcium oxide (quicklime, $\text{CaO}$) and carbon dioxide ($\text{CO}_2$). This is an important industrial process for manufacturing cement.
$\text{CaCO}_3\text{(s)} \xrightarrow{\text{Heat}} \text{CaO(s)} + \text{CO}_2\text{(g)}$
Example 3: Heating lead nitrate ($\text{Pb(NO}_3)_2$, white powder). It decomposes to lead oxide ($\text{PbO}$, yellow solid), nitrogen dioxide ($\text{NO}_2$, brown fumes), and oxygen gas ($\text{O}_2$).
$2\text{Pb(NO}_3)_2\text{(s)} \xrightarrow{\text{Heat}} 2\text{PbO(s)} + 4\text{NO}_2\text{(g)} + \text{O}_2\text{(g)}$
- Electrolytic Decomposition (Electrolysis): Decomposition caused by passing electric current.
Example: Electrolysis of water ($\text{H}_2\text{O}$). Water decomposes into hydrogen gas ($\text{H}_2$) and oxygen gas ($\text{O}_2$) when electric current is passed through it (often with a little acid added to make it conduct electricity). The volume of hydrogen gas collected at one electrode is twice the volume of oxygen gas collected at the other, consistent with the $2:1$ ratio of hydrogen to oxygen atoms in water.
$2\text{H}_2\text{O(l)} \xrightarrow{\text{Electricity}} 2\text{H}_2\text{(g)} + \text{O}_2\text{(g)}$
- Photochemical Decomposition (Photolysis): Decomposition caused by light energy.
Example 1: Exposing silver chloride ($\text{AgCl}$, white solid) to sunlight. It decomposes into silver metal ($\text{Ag}$, grey solid) and chlorine gas ($\text{Cl}_2$).
$2\text{AgCl(s)} \xrightarrow{\text{Sunlight}} 2\text{Ag(s)} + \text{Cl}_2\text{(g)}$
Example 2: Silver bromide ($\text{AgBr}$) also undergoes photochemical decomposition in sunlight, forming silver and bromine gas. These reactions are used in traditional black and white photography.
$2\text{AgBr(s)} \xrightarrow{\text{Sunlight}} 2\text{Ag(s)} + \text{Br}_2\text{(g)}$
Reactions that absorb energy are called endothermic reactions. Decomposition reactions are typically endothermic because they require energy input to break chemical bonds.
Example of an Endothermic Reaction (non-decomposition): Mixing barium hydroxide and ammonium chloride feels cold because the reaction absorbs heat from the surroundings.
1.2.3 Displacement Reaction
A displacement reaction is a type of chemical reaction where a more reactive element displaces (removes) a less reactive element from its compound.
Example: When an iron nail ($\text{Fe}$) is dipped into a copper sulphate solution ($\text{CuSO}_4$, blue colour), iron displaces copper from the copper sulphate solution. The iron nail becomes coated with brownish copper metal, and the blue colour of the copper sulphate solution fades due to the formation of iron sulphate ($\text{FeSO}_4$, which is typically green or colourless in dilute solution).
$\text{Fe(s)} + \text{CuSO}_4\text{(aq)} \longrightarrow \text{FeSO}_4\text{(aq)} + \text{Cu(s)}$
Here, iron is more reactive than copper, so it displaces copper from the copper sulphate solution.
Other Examples of Displacement Reactions:
- Zinc ($\text{Zn}$) reacting with copper sulphate ($\text{CuSO}_4$): Zinc is more reactive than copper.
$\text{Zn(s)} + \text{CuSO}_4\text{(aq)} \longrightarrow \text{ZnSO}_4\text{(aq)} + \text{Cu(s)}$
- Lead ($\text{Pb}$) reacting with copper chloride ($\text{CuCl}_2$): Lead is more reactive than copper.
$\text{Pb(s)} + \text{CuCl}_2\text{(aq)} \longrightarrow \text{PbCl}_2\text{(aq)} + \text{Cu(s)}$
The relative reactivity of elements determines which element can displace another. More reactive metals are generally higher in the reactivity series.
1.2.4 Double Displacement Reaction
In a double displacement reaction, there is an exchange of ions between two reactant compounds, leading to the formation of two new compounds.
These reactions often occur in aqueous solutions and can result in the formation of a precipitate, a gas, or water.
Example: Mixing a solution of sodium sulphate ($\text{Na}_2\text{SO}_4$) with a solution of barium chloride ($\text{BaCl}_2$). A white insoluble substance, barium sulphate ($\text{BaSO}_4$), is formed as a precipitate. Sodium chloride ($\text{NaCl}$) is also formed and remains dissolved in the solution.
$\text{Na}_2\text{SO}_4\text{(aq)} + \text{BaCl}_2\text{(aq)} \longrightarrow \text{BaSO}_4\text{(s)} \downarrow + 2\text{NaCl(aq)}$
Here, the sodium ions ($\text{Na}^+$) from $\text{Na}_2\text{SO}_4$ exchange partners with the barium ions ($\text{Ba}^{2+}$) from $\text{BaCl}_2$. Sodium combines with chloride ($\text{Cl}^-$) to form $\text{NaCl}$, and barium combines with sulphate ($\text{SO}_4^{2-}$) to form $\text{BaSO}_4$.
Reactions that produce a precipitate are also called precipitation reactions.
Example: Mixing lead(II) nitrate solution ($\text{Pb(NO}_3)_2$) and potassium iodide solution ($\text{KI}$) forms a yellow precipitate of lead(II) iodide ($\text{PbI}_2$) and potassium nitrate ($\text{KNO}_3$). This is a double displacement reaction.
$\text{Pb(NO}_3)_2\text{(aq)} + 2\text{KI(aq)} \longrightarrow \text{PbI}_2\text{(s)} \downarrow + 2\text{KNO}_3\text{(aq)}$
1.2.5 Oxidation And Reduction
Oxidation and reduction are fundamental concepts in chemistry that describe the transfer or sharing of electrons or the gain/loss of oxygen and hydrogen during chemical reactions.
Originally, these terms were defined based on the gain or loss of oxygen or hydrogen:
- Oxidation: The process involving the gain of oxygen or the loss of hydrogen by a substance during a reaction.
- Reduction: The process involving the loss of oxygen or the gain of hydrogen by a substance during a reaction.
Example: Heating copper powder ($\text{Cu}$, shiny brown) in air (oxygen, $\text{O}_2$). The copper reacts with oxygen to form black copper(II) oxide ($\text{CuO}$).
$2\text{Cu(s)} + \text{O}_2\text{(g)} \xrightarrow{\text{Heat}} 2\text{CuO(s)}$
Here, copper ($\text{Cu}$) gains oxygen, so it is oxidised to copper(II) oxide ($\text{CuO}$).
If hydrogen gas ($\text{H}_2$) is passed over the heated copper(II) oxide ($\text{CuO}$), the black coating turns brown as copper is recovered, and water ($\text{H}_2\text{O}$) is formed.
$\text{CuO(s)} + \text{H}_2\text{(g)} \xrightarrow{\text{Heat}} \text{Cu(s)} + \text{H}_2\text{O(l)}$
In this reaction:
- Copper(II) oxide ($\text{CuO}$) loses oxygen, so it is reduced to copper ($\text{Cu}$).
- Hydrogen ($\text{H}_2$) gains oxygen, so it is oxidised to water ($\text{H}_2\text{O}$).
Reactions where one substance is oxidised and another substance is reduced simultaneously are called oxidation-reduction reactions or redox reactions. Oxidation and reduction always occur together; one cannot happen without the other.
Other Examples of Redox Reactions:
- $\text{ZnO + C} \longrightarrow \text{Zn + CO}$ (ZnO is reduced, C is oxidised)
- $\text{MnO}_2 + 4\text{HCl} \longrightarrow \text{MnCl}_2 + 2\text{H}_2\text{O} + \text{Cl}_2$ (MnO₂ is reduced, HCl is oxidised)
A substance that causes oxidation (by providing oxygen or removing hydrogen) is called an oxidising agent. A substance that causes reduction (by providing hydrogen or removing oxygen) is called a reducing agent. In the example $\text{CuO} + \text{H}_2 \longrightarrow \text{Cu} + \text{H}_2\text{O}$, $\text{CuO}$ is the oxidising agent, and $\text{H}_2$ is the reducing agent.
1.3 Have You Observed The Effects Of Oxidation Reactions In Everyday Life?
Oxidation reactions are common in everyday life and can have noticeable effects, such as the degradation of metals and food.
1.3.1 Corrosion
Corrosion is the process where a metal is gradually degraded or eaten away by the reaction of its surface with substances in its environment, such as moisture, acids, gases (like oxygen, carbon dioxide, sulphur dioxide), etc.
This process is a type of oxidation reaction. The most common example is the rusting of iron, where iron reacts with oxygen and moisture to form reddish-brown hydrated iron oxides (rust). Other metals also corrode; silver tarnishes, forming a black coating of silver sulphide, and copper develops a green coating of basic copper carbonate.
Corrosion, particularly rusting of iron, is a significant problem that causes damage to structures, vehicles, ships, and objects made of metal, leading to considerable economic losses annually.
Methods like painting, oiling, greasing, galvanising (coating with zinc), electroplating, and making alloys are used to prevent or slow down corrosion.
1.3.2 Rancidity
Rancidity is the spoilage of food items containing fats and oils due to oxidation. When fats and oils are exposed to air, they undergo oxidation reactions, which break them down into compounds with unpleasant smells and tastes.
This change in smell and taste makes the food 'rancid' and unfit for consumption.
To prevent or slow down rancidity, several methods are used:
- Adding antioxidants to food. Antioxidants are substances that prevent oxidation.
- Storing food in airtight containers to minimise contact with oxygen.
- Packaging food in an atmosphere of nitrogen gas. Nitrogen is a relatively inert gas that replaces oxygen in the packaging (like in bags of chips), preventing oxidation of the fats and oils.
- Refrigeration slows down the rate of oxidation reactions.
Intext Questions
Page No. 6
Question 1. Why should a magnesium ribbon be cleaned before burning in air?
Answer:
Question 2. Write the balanced equation for the following chemical reactions.
(i) Hydrogen + Chlorine $→$ Hydrogen chloride
(ii) Barium chloride + Aluminium sulphate $→$ Barium sulphate + Aluminium chloride
(iii) Sodium + Water $→$ Sodium hydroxide + Hydrogen
Answer:
Question 3. Write a balanced chemical equation with state symbols for the following reactions.
(i) Solutions of barium chloride and sodium sulphate in water react to give insoluble barium sulphate and the solution of sodium chloride.
(ii) Sodium hydroxide solution (in water) reacts with hydrochloric acid solution (in water) to produce sodium chloride solution and water.
Answer:
Page No. 10
Question 1. A solution of a substance ‘X’ is used for whitewashing.
(i) Name the substance ‘X’ and write its formula.
(ii) Write the reaction of the substance ‘X’ named in (i) above with water.
Answer:
Question 2. Why is the amount of gas collected in one of the test tubes in Activity 1.7 double of the amount collected in the other? Name this gas.
Answer:
Page No. 13
Question 1. Why does the colour of copper sulphate solution change when an iron nail is dipped in it?
Answer:
Question 2. Give an example of a double displacement reaction other than the one given in Activity 1.10.
Answer:
Question 3. Identify the substances that are oxidised and the substances that are reduced in the following reactions.
(i) $4Na(s) + O_2(g) \rightarrow 2Na_2O(s)$
(ii) $CuO(s) + H_2(g) \rightarrow Cu(s) + H_2O(l)$
Answer:
Exercises
Question 1. Which of the statements about the reaction below are incorrect?
$2PbO(s) + C(s) \rightarrow 2Pb(s) + CO_2(g)$
(a) Lead is getting reduced.
(b) Carbon dioxide is getting oxidised.
(c) Carbon is getting oxidised.
(d) Lead oxide is getting reduced.
(i) (a) and (b)
(ii) (a) and (c)
(iii) (a), (b) and (c)
(iv) all
Answer:
Question 2. $Fe_2O_3 + 2Al \rightarrow Al_2O_3 + 2Fe$
The above reaction is an example of a
(a) combination reaction.
(b) double displacement reaction.
(c) decomposition reaction.
(d) displacement reaction.
Answer:
Question 3. What happens when dilute hydrochloric acid is added to iron fillings? Tick the correct answer.
(a) Hydrogen gas and iron chloride are produced.
(b) Chlorine gas and iron hydroxide are produced.
(c) No reaction takes place.
(d) Iron salt and water are produced.
Answer:
Question 4. What is a balanced chemical equation? Why should chemical equations be balanced?
Answer:
Question 5. Translate the following statements into chemical equations and then balance them.
(a) Hydrogen gas combines with nitrogen to form ammonia.
(b) Hydrogen sulphide gas burns in air to give water and sulpur dioxide.
(c) Barium chloride reacts with aluminium sulphate to give aluminium chloride and a precipitate of barium sulphate.
(d) Potassium metal reacts with water to give potassium hydroxide and hydrogen gas.
Answer:
Question 6. Balance the following chemical equations.
(a) $HNO_3 + Ca(OH)_2 \rightarrow Ca(NO_3)_2 + H_2O$
(b) $NaOH + H_2SO_4 \rightarrow Na_2SO_4 + H_2O$
(c) $NaCl + AgNO_3 \rightarrow AgCl + NaNO_3$
(d) $BaCl_2 + H_2SO_4 \rightarrow BaSO_4 + HCl$
Answer:
Question 7. Write the balanced chemical equations for the following reactions.
(a) Calcium hydroxide + Carbon dioxide $→$ Calcium carbonate + Water
(b) Zinc + Silver nitrate $→$ Zinc nitrate + Silver
(c) Aluminium + Copper chloride $→$ Aluminium chloride + Copper
(d) Barium chloride + Potassium sulphate $→$ Barium sulphate + Potassium chloride
Answer:
Question 8. Write the balanced chemical equation for the following and identify the type of reaction in each case.
(a) Potassium bromide(aq) + Barium iodide(aq) $→$ Potassium iodide(aq) + Barium bromide(s)
(b) Zinc carbonate(s) $→$ Zinc oxide(s) + Carbon dioxide(g)
(c) Hydrogen(g) + Chlorine(g) $→$ Hydrogen chloride(g)
(d) Magnesium(s) + Hydrochloric acid(aq) $→$ Magnesium chloride(aq) + Hydrogen(g)
Answer:
Question 9. What does one mean by exothermic and endothermic reactions? Give examples.
Answer:
Question 10. Why is respiration considered an exothermic reaction? Explain.
Answer:
Question 11. Why are decomposition reactions called the opposite of combination reactions? Write equations for these reactions.
Answer:
Question 12. Write one equation each for decomposition reactions where energy is supplied in the form of heat, light or electricity.
Answer:
Question 13. What is the difference between displacement and double displacement reactions? Write equations for these reactions.
Answer:
Question 14. In the refining of silver, the recovery of silver from silver nitrate solution involved displacement by copper metal. Write down the reaction involved.
Answer:
Question 15. What do you mean by a precipitation reaction? Explain by giving examples.
Answer:
Question 16. Explain the following in terms of gain or loss of oxygen with two examples each.
(a) Oxidation
(b) Reduction
Answer:
Question 17. A shiny brown coloured element ‘X’ on heating in air becomes black in colour. Name the element ‘X’ and the black coloured compound formed.
Answer:
Question 18. Why do we apply paint on iron articles?
Answer:
Question 19. Oil and fat containing food items are flushed with nitrogen. Why?
Answer:
Question 20. Explain the following terms with one example each.
(a) Corrosion
(b) Rancidity
Answer: